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2 years ago

Write the function of force

Physics

1 answer:

Inga [223]2 years ago

3 0

Answer:

Force can make a body that is at rest to move. It can stop a moving body or slow it down. It can accelerate the speed of a moving body. It can also change the direction of a moving body along with its shape and size.

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The answer is C, method?

Arturiano [62]

Answer:

Numbers with more number

Explanation:

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4 0

3 years ago

The water behind Grand Coulee Dam is 1000 m wide and 200 m deep. Find the hydrostatic force on the back of the dam. (Hint: the t

Vika [28.1K]

Answer:

The hydro static force on the back of the dam is $1.96\times10^{11}\ N$

Explanation:

Given that,

Width b= 1000 m

Depth d= 200 m

We need to calculate the average pressure

Using formula of average pressure

$P_{avg}=\rho\times g\times d_{avg}$

Put the value into the formula

$P_{avg}=1000\times9.8\times100$

$P_{avg}=980000\ Pa$

We need to calculate the hydro static force on the back of the dam

Using formula of force

$F = P_{avg}\times A$

Put the value into the formula

$F = 980000\times1000\times200$

$F=1.96\times10^{11}\ N$

Hence, The hydro static force on the back of the dam is $1.96\times10^{11}\ N$

7 0

3 years ago

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

Sunny_sXe [5.5K]

Answer:

a) 5.09 seconds

b) 107.07 meters

Explanation:

a) As we know

$t_2- t_1 = \sqrt{\frac{2 X}{a} }$

Substituting the given values we get

$t_2 - t_1 = \sqrt{\frac{2 * 52}{4} } \\t_2 - t_1 = 5.09$

It takes 5 .09 s for the motorcycle to accelerate until it catches up with the car

$X_{t`2} = v_i \sqrt{\frac{2X}{a} } + 0.5 a\sqrt{\frac{2X}{a} }\\X_{t`2} = (v_i + 0.5 a) \sqrt{\frac{2X}{a} }\\X_{t`2} = ( 19 + 2) \sqrt{\frac{2* 52}{4} }\\X_{t`2} = 21 * 5.09\\X_{t`2} = 107.07$

4 0

3 years ago

The coefficient of static friction between car's tires and a level road is 0.80 If car to be stopped in time of 3.0 sec its spee

Vlad1618 [11]

Answer:

23.5 m/s

Explanation:

The velocity of the car in decelerated motion is given by

v = u + at

where

v = 0 is the final velocity

u is the initial velocity

a is the acceleration of the car

t = 3.0 s is the time it takes for the car to stop

The acceleration of the car is given by the frictional force, which is the only force acting on the car along the direction of motion, so:

$ma = -\mu mg\\a = -\mu g = -(0.80)(9.8 m/s^2)=-7.84 m/s^2$

where

$\mu=0.80$ is the coefficient of friction

Solving the previous equation for u, we find the initial velocity:

$u=v-at=0-(-7.84 m/s^2)(3.0 s)=23.5 m/s$

4 0

4 years ago

At time t=0 a 2150 kg rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. This forc

vredina [299]

Answer:

two people who are not going to be able to make it to the office and I will be there at the house and I will be there in a few minutes and I'll be there in a few

8 0

3 years ago

Write the function of force​

Write the function of force