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PSYCHO15rus [73]
3 years ago
11

THIS IS A SCIENCE QUESTION IF THESE ARNT ANSWERED IM GOING TO FAIL SCIENCE

Physics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

1.a storm with a violent wind, in particular a tropical cyclone in the Caribbean.

2.The Eye of a Hurricane. The eye is the region at the center of the hurricane, which is roughly circular in shape and usually has calm weather.

3.Hurricanes form over the ocean, often beginning as a tropical wave—a low pressure area that moves through the moisture-rich tropics, possibly enhancing shower and thunderstorm activity.  

4.When the surface water is warm, the storm sucks up heat energy from the water, just like a straw sucks up a liquid. This creates moisture in the air. If wind conditions are right, the storm becomes a hurricane. This heat energy is the fuel for the storm.

5.a rising of the sea as a result of atmospheric pressure changes and wind associated with a storm.

6.A hurricane dies down when it loses its energy source, which is usually warm water at the surface of the ocean.

7.Hurricane Katrina was so destructive because of a bunch of events that happened in just the right way. First, understand that Katrina was at one point a Category 5 storm and was predicted to hit New Orleans as a Category 4. It weakened to a Cat 3 and veered ever so slightly to the east, making the damage far less than it could have been.

Explanation:

hope this helps

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Find the velocity. 10 points. Will give brainliest!
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6.060606...

Explanation:

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4 years ago
A cylinder of mass 14.0 kg rolls without slipping on a horizontal surface. At a certain instant its center of mass has a speed o
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Answer:

a) 567J

b) 283.5J

c)850.5J

Explanation:

The expression for the translational kinetic energy is,

E_r = \frac{1}{2} mv^2

Substitute,

14kg for m

9m/s for v

E_r = \frac{1}{2} (14) (9)^2\\= 567J

The translational kinetic energy of the center of mass is 567J

(B)

The expression for the rotational kinetic energy is,

E_R = \frac{1}{2} Iw^2

The expression for the moment of inertia of the cylinder is,

I = \frac{1}{2} mr^2

The expression for angular velocity is,

w = \frac{v}{r}

substitute

1/2mr² for I

and vr for w

in equation for rotational kinetic energy as follows:

E_R = (\frac{1}{2}) (\frac{1}{2} mr^2)(\frac{v}{r} )^2

= \frac{mv^2}{4}

E_R = \frac{14 \times 9^2 }{4} \\\\= 283.5J

The rotational kinetic energy of the center of mass is 283.5J

(c)

The expression for the total energy is,

E = E_r + E_R\\\\

substitute 567J for E(r) and 283.5J for E(R)

E = 567J + 283.5\\= 850.5J

The total energy of the cylinder is 850.5J

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Answer:

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