Answer:
1. v₂ = 12.43 m/s
2. I₁ = - 80 N.s
3. I₂ = 80 N.s
Explanation:
Consider the following data given in the question:
m₁ = mass of the Cart 1 = 16 kg
m₂ = mass of the Cart 2 = 7 kg
u₁ = velocity of cart 1 before collision = 4 m/s
u₂ = velocity of cart 2 before collision = 1 m/s
v₁ = velocity of cart 1 after collision = - 1 m/s
v₂ = velocity of cart 2 after collision = ?
1.
Applying the law of conservation of momentum:
![m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}\\(16\ kg)(4\ m/s)+(7\ kg)(1\ m/s)=(16\ kg)(-1\ m/s)+(7\ kg)(v_{2})\\v_{2} = \frac{87\ kg.m/s}{7\ kg}](https://tex.z-dn.net/?f=m_%7B1%7Du_%7B1%7D%20%2B%20m_%7B2%7Du_%7B2%7D%20%3D%20m_%7B1%7Dv_%7B1%7D%20%2B%20m_%7B2%7Dv_%7B2%7D%5C%5C%2816%5C%20kg%29%284%5C%20m%2Fs%29%2B%287%5C%20kg%29%281%5C%20m%2Fs%29%3D%2816%5C%20kg%29%28-1%5C%20m%2Fs%29%2B%287%5C%20kg%29%28v_%7B2%7D%29%5C%5Cv_%7B2%7D%20%3D%20%5Cfrac%7B87%5C%20kg.m%2Fs%7D%7B7%5C%20kg%7D)
<u>v₂ = 12.43 m/s</u>
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2.
Impulse of cart 1 = I₁ = m₁(v₁ - u₁)
I₁ = (16 kg)(- 1 m/s - 4 m/s)
<u>I₁ = - 80 N.s</u>
<u></u>
3.
Impulse of cart 2 = I₂ = m₂(v₂ - u₂)
I₂ = (7 kg)(12.43 m/s - 1 m/s)
<u>I₂ = 80 N.s</u>
In physics mass-energy equivalence is the principal that anything having mass has an equivalent amount of energy and vise versa.
The answer is D, human.
Happy Friday!!!
Answer:
10.85 m/s
Explanation:
m = 1200 kg, h1 = 19 m, h2 = 13 m
Let v be the velocity
Use the conservation of energy
Potential energy at 19 m = Potential energy at 13 m + kinetic energy
m x g x h1 = m x g x h2 + 1/2 mv^2
m x g (h1 - h2) = 0.5 x m v^2
g (h1 - h2) = 0.5 v^2
9.8 (19 - 13) = 0.5 x v^2
v = 10.85 m/s
Hi,
The force that acts on hydraulic machine is heavy therefore the content must be something that cannot be compressed by that kind of force, the gas can easily be compressed while a liquid is nearly impossible to.