Which choice has prokaryotic cells?

The three beakers shown below contain solutions of [cof6]3–, [co(nh3)6]3+, and [co(cn)6]3–. based on the colors of the three sol

vitfil [10]

[Co(CN)₆]³⁻ → Yellow
[Co(NH₃)₆]³⁺ → Orange
[CoF₆]³⁻ → Blue
Explanation:
- All the given compounds have octahedral geometry but the ligand in each are different with the same metal ion.

- Ligands strength order: CN⁻ > NH₃ > F⁻

- The ligand CN will act as a strong field ligand so that the splitting is maximum when compared to NH₃ and F⁻

- If the splitting is more, the energy required for transition is more, and the wavelength is inversely proportional to energy.

- So CN complex will absorb at lower wavelength (yellow color)

3 0

3 years ago

What is the molarity of a solution containing 60. grams of NaOH dissolved in 400. mL of water?

Hunter-Best [27]

Answer: 3.75 M

Explanation:

400 mL = 0.4 L

NaOH has a molar mass of around 40 g/mol.

$\frac{60 grams}{40 g/mol}$ = 1.5 moles

Molarity = $\frac{1.5 moles}{0.4 Liters}$ = 3.75 M

8 0

3 years ago

2. Combine lead (II) nitrate and potassium iodide solutions.<br> Pb(NO3)2+ Kl →

Shtirlitz [24]

Answer:

Pb(NO3)2 + KI = KNO3 + PbI2

7 0

3 years ago

A field worker is exposed to a xylene for a duration of 8 weeks at 40 hrs/wk. The concentration of xylene in the workplace is 40

Andrej [43]

Answer:

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

Explanation:

Number of hours worker exposed to xylene = $40 hr/week\times 8 week = 320 hours$

The concentration of xylene in the workplace = $40 \mu g/m^3$

The worker is inhaling air at a rate of $0.9 m^3/hr$ .

Amount xylene inhaled by worker in an hour :

= $40\mu g/m^3\times 0.9 m^3/hr=36 \mu g/hr$

Amount xylene inhaled by worker in 320 hours:

$36 \mu g/hr\times 320 hr=11,520 \mu g=11,520\times 0.001 mg=11.520 mg$

1 μg = 0.001 mg

Amount xylene inhaled by worker in 320 hours = 11.520 mg

1 day = 24 hours

Amount xylene inhaled by worker in 1 day:

$\frac{24}{320}\times 11.520 mg=0.864 mg$

Assuming 70 kg body mass, the chronic daily intake of xylene :

$\frac{0.864 mg/day}{70 kg}=0.01234 mg/ kg day\approx 0.012 mg/ kg day$

The chronic daily intake during the period of exposure is most nearly 0.012 mg/kg day.

5 0

3 years ago

While working near a radioactive mine, workers usually wear heavy plastic suits. These suits protect them from all but

Vaselesa [24]

The appropriate response is gamma radiation. Alpha particles can be halted via air. UV radiation can be halted by a typical layer of clothing.Beta particles can be ceased by the thick plastic suit. Just gamma radiation can enter the substantial suit. It must be halted by thick dividers of lead or cement.

4 0

3 years ago

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