Answer:
43.2 mol C
115 mol H
158 mol of atoms
Explanation:
Step 1: Given data
Moles of C₃H₈: 14.4 mol
Step 2: Calculate the number of moles of C
The molar ratio of C₃H₈ to C is 1:3. The moles of C are 3/1 × 14.4 mol = 43.2 mol.
Step 3: Calculate the number of moles of H
The molar ratio of C₃H₈ to H is 1:(. The moles of H are 8/1 × 14.4 mol = 115 mol.
Step 4: Calculate the total number of moles of atoms
n = nC + nH = 43.2 mol + 115 mol = 158 mol
Answer:
The mathematical equation, N = n × NA, can be used to find the number of atoms, ions or molecules in any amount (in moles) of atoms, ions or molecules: 10 moles of helium atoms = 10 × (6.022 × 1023) = 6.022 × 1024 helium atoms.
Explanation:
She would divide that mass of each element by it molar mass the answer is C <span />
Do you have the reaction and coefficients?
the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g
The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn
3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2
the formula is n= mass/M so, now substituting values
m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3
so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g
so mass of aluminum oxide obtained = 1.36g
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