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Nitella [24]
1 year ago
5

A sample of X is carefully weighed and put inside a sealed calorimeter. The calorimeter is heated electrically, and the amount o

f heat added determined by monitoring the electrical current used. The temperature of X is carefully measured, and from the temperature change and the amount of heat added the value of H
may be calculated.
Is this a physical or chemical property?
Chemistry
1 answer:
mixer [17]1 year ago
8 0

The value of the heat of combustion (H) that is calculated here is a chemical property.

<h3>What is the heat of combustion?</h3>

The heat of combustion is the energy that is given up when a substance is burnt in a calorimeter. The heat of combustion is often measured by the use of a calorimeter.

Hence, the value of the heat of combustion (H) that is calculated here is a chemical property.

Learn more about heat of combustion:brainly.com/question/14317568

#SPJ1

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Partner Namets) For each of the following reactions carried out: Write the balanced chemical equation, the full ionic equation,
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Answer : The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

Reactants are lead nitrate and potassium iodide.

Products are lead iodide and potassium nitrate.

The spectator ions are, K^+,NO_3^-

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When potassium iodide react with lead nitrate then it gives potassium nitrate and lead iodide as a product.

The full balanced ionic equation will be,

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbI_2(s)

The ionic equation in separated aqueous solution will be,

2K^+(aq)+2I^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow PbI_2(s)+2K^+(aq)+2NO_3^{-}(aq)

In this equation, K^+\text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Pb^{2+}(aq)+2I^{-}(aq)\rightarrow PbI_2(s)

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