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Yuri [45]
2 years ago
5

How many moles are in 20 grams of O₂ gas?

Chemistry
1 answer:
Dima020 [189]2 years ago
4 0
20 g O2 x 1 mol O2/32 g O = 0.625 mol O2
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Answer please correctly
sladkih [1.3K]

Answer:

the correct answere to that is q

6 0
3 years ago
Read 2 more answers
If i have 8 L of 0.25 M solution, how many miles of MgCl2 are present
qaws [65]

Answer:

2 moles

Explanation:

The following were obtained from the question:

Molarity = 0.25 M

Volume = 8L

Mole =?

Molarity is simply defined as the mole of solute per unit litre of solution. It is represented mathematically as:

Molarity = mole of solute/Volume of solution.

With the above equation, we can easily find the number of mole of MgCl2 present in 8 L of 0.25 M MgCl2 solution as follow:

Molarity = mole of solute/Volume of solution.

0.25 = mole of MgCl2 /8

Cross multiply to express in linear form

Mole of MgCl2 = 0.25 x 8

Mole of MgCl2 = 2 moles

Therefore, 2 moles of MgCl2 are present in 8 L of 0.25 M MgCl2 solution

4 0
3 years ago
The volume of a sample of nitrogen is 6.00 liters at 35oC and 0.75 atm. What volume will it occupy at STP?
joja [24]
The  volume that  will  occupy  at STP  is  calculated   as  follows
by use  of ideal  gas  equation
that is  PV=nRT  where n  is  number of  moles  calculate  number of moles

n= PV/RT
p=0.75 atm
V=6.0  L
R = 0.0821  L.atm/k.mol
T=  35  +273= 308k
n=?

n=  (o.75  atm  x  6.0 L)/( 0.0821 L.atm/k.mol  x 308 k)=  0.178 moles

Agt  STP  1 mole=  22.4 L  what obout  0.178 moles

=  22.4  x0.178moles/ 1moles =3.98 L( answer C)
3 0
3 years ago
What is the mass of a substance in 0.5 mol of nh3​
KATRIN_1 [288]

Answer:

17 g/mol

Explanation:

don't worry tama yan

6 0
3 years ago
When planning a simple experiment, what does it mean to “test one variable”?
SSSSS [86.1K]

Answer:

I believe the answer is "b". "During the experiment, the scientist has only one element, or variable, that is changed to test the hypothesis."

Explanation:

I remember from last year but I'm not totally sure. Good luck!

3 0
3 years ago
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