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ziro4ka [17]
2 years ago
10

What is the inverse of this function? 8v, for x > 0

Mathematics
1 answer:
tia_tia [17]2 years ago
8 0

Answer:

f(x) = (x/8)^2       for x ≥ 0

Step-by-step explanation:

y = 8 sqrt x      switch   x and y

x = 8 sqrt y       now solve for y

(x/8)^2 = y

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Find the area of the shaded region.​​
earnstyle [38]

There are four parts of a circle, so you have to find out the area of the circle:-

10 cm=Radius

10^{2}=100

\pi=3.14

3.14*100=314 cm^{2}

Now, find the area of the square box:-

Since half the side of the square is 10 cm, the total length of one side is 2*10 which is 20 cm.

Area=S*S

=20*20=400 cm^{2}

Now subtract the area of the box from the area of the square:-

400-314= 86 cm^{2}

That is the area of the shaded part.

Happy to help you!

8 0
3 years ago
What is the slope of the line that passes through (5,-4) and (2,2)
maxonik [38]
The slope of this line is -2
4 0
3 years ago
Read 2 more answers
Can you please help me with this question. ​
blondinia [14]

Answer:

<h3>a. </h3>

Step-by-step explanation:

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4 0
3 years ago
the formula to find the period of orbit a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbits mean radius. If y
Oxana [17]

Answer:

<u>The correct answer is r = ∛GM*T²/4π²</u>

Step-by-step explanation:

Let's rewrite the formula to find the period of orbit of a satellite around a planet, to solve for r, this way:

T^2=(4pi^2/GM)r^3

T² = (4π²/GM) * r³

r³ = T²/ (4π²/GM)

r³ = T² * GM/4π²

r³ = GMT²/4π²

∛r³ = ∛GM*T²/4π²

r = ∛GM*T²/4π²

<u>The correct answer is r = ∛GM*T²/4π²</u>

7 0
3 years ago
2) In 1000 sq. meter of land a farmer cultivated 765 kg of rice with the wastage of 23.5%. I) Find the weight of the wastage. II
LiRa [457]

Answer:

Weight of wastage=179.775kg

weight of rice cultivated= 585.225 kg

percentage of rice cultivated=76.5%

Step-by-step explanation:

Area of land=100 square meters

Cultivated rice=765kg

Wastage=23.5%

1) Weight of the wastage=23.5% of 765kg

=23.5/100 × 765

=17977.5 / 100

=179.775 kg

2) Weight and percentage of rice cultivated.

weight of rice cultivated = 765 kg - 179. 775 kg

= 585.225 kg

percentage of rice cultivated = 100 - 23.5

= 76.5%

3) if area is increased 40 times in size

New area=1000 square meters × 40

=40,000 square meters

Cultivated rice= 765kg × 40

=30,600 kg

Cultivated rice excluding wastage=585.225 kg × 40

=23,409 kg

8 0
3 years ago
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