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2 years ago

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If a person weighs 87lbs and has to be given a drug with a dosage of 50 milligrams per kilogram body weight, how many grams of t

he drug does the person have to take?

1 answer:

Katarina [22]2 years ago

7 0

Answer:

1 957,5

Explanation:

87libs=39.5kg that equals 50=1.957.5

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The number of nucleons in an atom is the atom's (atomic, mass) number.

ELEN [110]

The number of neutrons in an atom is the number of particles present in its nucleus.
The atomic number is the number of protons whereas the mass number is the number of protons and number of neutrons together
This implies that the number of neutrons is the atom's mass number

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2 years ago

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When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass o

irakobra [83]

The mass of sodium sulfite that was used will be 1,890 grams.

<h3>Stoichiometric problems</h3>

First, the equation of the reaction:

$NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2$

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.

Mole of 960 grams SO2 = 960/64 = 15 moles

Equivalent mole of sodium sulfite that reacted = 15 moles

Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

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1 year ago

Jim drops an iron magnet during a chemistry lab experiment. He finds that it is no longer magnetic. What has happened in terms o

jok3333 [9.3K]

Answer: option A.

A physical change occurred in which the iron remained iron, but lost one of its physical properties

Explanation: magnetization and demagnetization is a physical change as no new substance is form and it is easily reversed. When an iron rod is magnetized, it can loss it magnetic property by hitting it. So when an iron rod which is magnetized falls from a height it can also loss its magnetic property

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3 years ago

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A solution of CaCl 2 in water forms a mixture that is 42.0 % calcium chloride by mass. If the total mass of the mixture is 839.6

Lerok [7]

Answer : The masses of calcium chloride and water used were, 352.6 g and 487.0 g.

Explanation :

As we are given that 42.0 % calcium chloride by mass that means 42.0 grams of calcium chloride present in 100 grams of solution.

In the solution or mixture, 42.0 % calcium chloride and 58.0 % (100-42.0=58.0) water.

Now we have to determine the mass of calcium chloride for 839.6 grams of solution.

As, 100 grams of solution contains 42.0 grams of calcium chloride

So, 839.6 grams of solution contains $\frac{42.0}{100}\times 839.6=352.6$ grams of calcium chloride

Thus, the mass of calcium chloride used is, 352.6 grams.

Now we have to determine the mass of water.

Mass of water = Mass of solution - Mass of calcium chloride

Mass of water = 839.6 g - 352.6 g

Mass of water = 487.0 g

Thus, the mass of water used is, 487.0 grams.

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2 years ago

A mixture with H2 and He exerts a total pressure of 0.48 atm. If there is 1.0 g of H2 and 1.0 g of He in the mixture, what is th

lara [203]

Answer is: the partial pressure of the helium gas is 0.158 atm.

p(mixture) = 0.48 atm; total pressure.

m(H₂) = 1.0 g; mass of hydrogen gas.

n(H₂) = m(H₂) ÷ M(H₂).

n(H₂) = 1.0 g ÷ 2 g/mol.

n(H₂) = 0.5 mol; amount of hydrogen.

m(He) = 1.0 g; mass of helium.

n(He) = 1 g ÷ 4 g/mol.

n(He) = 0.25 mol; amount of helium.

χ(H₂) = 0.5 mol ÷ 0.75 mol.

χ(H₂) = 0.67; mole fraction of hydrogen.

χ(He) = 0.25 mol ÷ 0.75 mol.

χ(He) = 0.33; mole fraction of helium.

p(He) = 0.33 · 0.48 atm.

p(He) = 0.158 atm; the partial pressure of the helium gas.

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3 years ago