Answer:
K_a = 8,111 J
Explanation:
This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved
initial instant. Just before dropping the particles
p₀ = 0
final moment
p_f = m_a v_a + m_b v_b
p₀ = p_f
0 = m_a v_a + m_b v_b
tells us that
m_a = 8 m_b
0 = 8 m_b v_a + m_b v_b
v_b = - 8 v_a (1)
indicate that the transfer is complete, therefore the kinematic energy is conserved
starting point
Em₀ = K₀ = 73 J
final point. After separating the body
Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²
K₀ = K_f
73 = ½ m_a (v_a² + v_b² / 8)
we substitute equation 1
73 = ½ m_a (v_a² + 8² v_a² / 8)
73 = ½ m_a (9 v_a²)
73/9 = ½ m_a (v_a²) = K_a
K_a = 8,111 J
Answer:
Weight of the woman in Newton
![x = 698.6 \ N](https://tex.z-dn.net/?f=x%20%3D%20%20698.6%20%5C%20%20N)
Mass of the woman in slug
![Mass = 4.86 \ slug](https://tex.z-dn.net/?f=Mass%20%3D%20%204.86%20%5C%20%20slug)
Mass of the woman in kg
![Mass = 16 \ kg](https://tex.z-dn.net/?f=Mass%20%3D%20%2016%20%5C%20%20kg)
My weight in Newton
![W = 784 \ N](https://tex.z-dn.net/?f=W%20%3D%20%20784%20%5C%20%20N)
Explanation:
From the question we are told that
The weight of the woman in pounds is ![W = 157 \ lb](https://tex.z-dn.net/?f=W%20%3D%20157%20%5C%20lb)
Converting to Newton
1 N = 0.22472 lb
x N = 157
=> ![x = \frac{157 * 1}{0.22472}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B157%20%2A%20%201%7D%7B0.22472%7D)
=> ![x = 698.6 \ N](https://tex.z-dn.net/?f=x%20%3D%20%20698.6%20%5C%20%20N)
Obtaining the mass in slug
![Mass = \frac{W}{g}](https://tex.z-dn.net/?f=Mass%20%3D%20%20%5Cfrac%7BW%7D%7Bg%7D)
Here ![g = 32.2 ft/s^2](https://tex.z-dn.net/?f=g%20%3D%20%2032.2%20ft%2Fs%5E2)
So
![Mass = \frac{157 }{32.2}](https://tex.z-dn.net/?f=Mass%20%3D%20%20%5Cfrac%7B157%20%7D%7B32.2%7D)
![Mass = 4.86 \ slug](https://tex.z-dn.net/?f=Mass%20%3D%20%204.86%20%5C%20%20slug)
Obtaining the mass in kilogram
![Mass = \frac{W}{g}](https://tex.z-dn.net/?f=Mass%20%3D%20%20%5Cfrac%7BW%7D%7Bg%7D)
Here ![g = 9.8 \ m/s](https://tex.z-dn.net/?f=g%20%3D%20%209.8%20%5C%20%20m%2Fs)
So
![Mass = \frac{157 }{9.8}](https://tex.z-dn.net/?f=Mass%20%3D%20%20%5Cfrac%7B157%20%7D%7B9.8%7D)
![Mass = 16 \ kg](https://tex.z-dn.net/?f=Mass%20%3D%20%2016%20%5C%20%20kg)
Generally weight is mathematically represented as
![W = m * g](https://tex.z-dn.net/?f=W%20%3D%20%20m%20%2A%20%20g)
Given that my mass is 80 kg then my weight is
![W = 80 *9.8](https://tex.z-dn.net/?f=W%20%3D%20%20%2080%20%2A9.8)
![W = 784 \ N](https://tex.z-dn.net/?f=W%20%3D%20%20784%20%5C%20%20N)
Answer:
ReCrystallization
Contact pressure causing grains to "grow" together.
It's a metamorphic process used to rearrange the atoms of the minerals in order to modify them in to the required form under the specific temperature and pressure. For example conversion of limestone into marble.
<em>Cementation:</em>
Precipitation of bonding agents between grains.
Cementation is the process in which the minerals in the form of fluid fills in spaces between the grains and binds them together upon crystallizing.
<em>Compaction:</em>
Increase in density due to weight of overburden.
Compaction as it's name indicate is the compaction of the sediments due to the heavy weight of the rocks which reduce their size and increase their density.