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Andreyy89
3 years ago
10

A sprinter starts from rest and reaches a speed of 15 m/s in 4.25 s. Find his acceleration

Physics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

a=3.53 m/s^2

Explanation:

Vo=0 m/s (because he is not moving at the start)

V1=15 m/s

t= 4.25 s

a = (V1-Vo) / t = 15/4.25 = 3.53 m/s^2

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The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance D_{A} beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed v_{A}. Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed v_{B}, which is greater than v_{A}.

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Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

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              Part B: x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}

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Car B started at the starting line. So, its equation is

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t(v_{B}-v_{A})=D_{A}

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Car B meet with Car A after t=\frac{D_{A}}{v_{B}-v_{A}} units of time.

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Since Car B started at the starting line, the distance Car B will be when it passes Car A is x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}} units of distance.

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