The power developed is 500 W ( to the nearest Watt)
Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.
Therefore,
Substitute the given values of force , displacement and time
Thus the Power can be rounded off to the nearest value of 500 W
1935.5 N is the "net force" acting on a car.
<u>Explanation</u>:
Given that,
Mass of the car is 790 kg.
Velocity of the car is 7 m/s. (v)
It turned around with 20 m. (r)
We know that, Net force = m × a
Now, Net force = m × a
Net force = 790 × 2.45
Net force = 1935.5 N
Y - yo = Vo*t - g * (t^2) / 2
Vo = - 9.0 m/s
t = 0.50 s
=> y - yo = -9.0 m/s * 0.5 s - 9.8 m/s^2 * (0.5s)^2 / 2 = - 4.5m - 1.225m = - 5.725 m.
Answer: option c) - 5.7
