Answer:
the frequency of this mode of vibration is 138.87 Hz
Explanation:
Given;
length of the copper wire, L = 1 m
mass per unit length of the copper wire, μ = 0.0014 kg/m
tension on the wire, T = 27 N
number of segments, n = 2
The frequency of this mode of vibration is calculated as;
Therefore, the frequency of this mode of vibration is 138.87 Hz
Answer:
$175
Explanation:
Insurance premium is expressed as a rate $1000
($3.50 per $1000)
Therefore;
Annual premium= $50000x$3.50/$1000
= $175
Anytime that an unstable nucleus emits alpha or bets particles, the number of protons and neutrons changes. ... In the fission process, when the nucleus splits, both neutrons and energy are released
A possible effect is the risk of Icecaps melted
Answer:
The two answers are in the explanation
Explanation:
Please find the attached files for the solution
