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Whitepunk [10]
3 years ago
11

The four tires of an automobile are inflated to a gauge pressure of 2.2 ✕ 105 Pa. Each tire has an area of 0.022 m2 in contact w

ith the ground. Determine the weight of the automobile.
Physics
1 answer:
Trava [24]3 years ago
7 0

Answer:

P =\frac{F}{A}

And solving for F we got:

F = PA

And replacing we got:

F = 2.2x10^5 Pa * 0.088 m^2 =19360 N

And if we want the mass we can solve from this formula:

F =mg

With g=9.8 m/s^2 the gravity

Explanation:

For this case we can find the total area of the 4 tires and we got:

A = 4*0.022 m^2 = 0.088m^2

Now we know that the total pressure is:

P=2.2 x10^5 Pa

And then we can find the weight with from this formula:

P =\frac{F}{A}

And solving for F we got:

F = PA

And replacing we got:

F = 2.2x10^5 Pa * 0.088 m^2 =19360 N

And if we want the mass we can solve from this formula:

F =mg

With g=9.8 m/s^2 the gravity

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  W / A = 39200 kg / m²

Explanation:

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           F = W

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         W = mg

We use the concept of density

        ρ = m / V

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The volume of the water column is

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We replace

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On the other side the cylinder cover has a pressure

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We match the two equations

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