consider the motion in x-direction
= initial velocity in x-direction = ?
X = horizontal distance traveled = 100 m
= acceleration along x-direction = 0 m/s²
t = time of travel = 4.60 sec
Using the equation
X = t + (0.5) t²
100 = (4.60)
= 21.7 m/s
consider the motion along y-direction
= initial velocity in y-direction = ?
Y = vertical displacement = 0 m
= acceleration along x-direction = - 9.8 m/s²
t = time of travel = 4.60 sec
Using the equation
Y = t + (0.5) t²
0 = (4.60) + (0.5) (- 9.8) (4.60)²
= 22.54 m/s
initial velocity is given as
= sqrt(()² + ()²)
= sqrt((21.7)² + (22.54)²) = 31.3 m/s
direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg
You can look at groups in the same group (the columns), since they tend to have similar properties. For example, the alkali metals in group one react aggressively with water and form white compounds.
Answer:
200 N/m
20 rad/s
0.31415 seconds
3.18309 Hz
Explanation:
m = Mass of glider = 0.5 kg
x = Displacement of spring
F = Force on spring = 6 N
From Hooke's law we have relation
The spring constant is 200 N/m
Angular frequency is given by
The angular frequency is 20 rad/s
Frequency is given by
The frequency is 3.18309 Hz
Time period is given by
The time period is 0.31415 seconds