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Whitepunk [10]
2 years ago
11

The four tires of an automobile are inflated to a gauge pressure of 2.2 ✕ 105 Pa. Each tire has an area of 0.022 m2 in contact w

ith the ground. Determine the weight of the automobile.
Physics
1 answer:
Trava [24]2 years ago
7 0

Answer:

P =\frac{F}{A}

And solving for F we got:

F = PA

And replacing we got:

F = 2.2x10^5 Pa * 0.088 m^2 =19360 N

And if we want the mass we can solve from this formula:

F =mg

With g=9.8 m/s^2 the gravity

Explanation:

For this case we can find the total area of the 4 tires and we got:

A = 4*0.022 m^2 = 0.088m^2

Now we know that the total pressure is:

P=2.2 x10^5 Pa

And then we can find the weight with from this formula:

P =\frac{F}{A}

And solving for F we got:

F = PA

And replacing we got:

F = 2.2x10^5 Pa * 0.088 m^2 =19360 N

And if we want the mass we can solve from this formula:

F =mg

With g=9.8 m/s^2 the gravity

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1. Which statement about friction is true?(1 point) A. Static friction and kinetic friction in a system always act in the same d
ArbitrLikvidat [17]

Answer:

true 1Ay 2D

Explanation:

1) In this exercise you are asked to investigate which statements are true

A) True. The friction force opposes the movement caused by the external force,

B) False. Mantuano in the opposite direction force

C) False. The static and scientific friction force act in the same direction, since the second appears when the movement does not start and the static friction decreases.

D) Fale the static and kinetic friction forces act in the same direction

2) How to overcome friction on a ramp

A) False. If the texture of the surface becomes rough, the friction force increases

B) False. Pressing the brick against the surface increases the normal and as the friction is proportional to the normal, it also increases

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D) True. When lifting the board, the weight component increases and therefore can become greater than the friction

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3 0
2 years ago
In the figure below, this “double” nozzle discharges water (at 10°C, density= 1000 kg/m3) into the atmosphere at a rate of 0.50
dezoksy [38]

Answer:

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8 0
2 years ago
A 54 kg man holding a 0.65 kg ball stands on a frozen pond next to a wall. He throws the ball at the wall with a speed of 12.1 m
Inessa [10]

Answer:

The velocity of the man is 0.144 m/s

Explanation:

This is a case of conservation of momentum.

The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.

Mass of ball = 0.65 kg

Mass of the man = 54 kg

Velocity of the ball = 12.1 m/s

Before collision, momentum of the ball = mass x velocity

= 0.65 x 12.1 = 7.865 kg-m/s

After collision the momentum of the man and ball system is

(0.65 + 54)Vf = 54.65Vf

Where Vf is their final common velocity.

Equating the initial and final momentum,

7.865 = 54.65Vf

Vf = 7.865/54.65 = 0.144 m/s

4 0
2 years ago
A wheel on a car is rolling without slipping along level ground. The speed of the car is 36 m/s. The wheel has an outer diameter
lutik1710 [3]

Answer:

The speed of the top of the wheel is twice the speed of the car.

That is: 72  m/s

Explanation:

To find the speed of the top of the wheel, we need to combine to velocities: the tangential velocity of the rotating wheel due to rotational motion (v_t=\omega\,R=\omega\,(0.25\,m)\,) - with \omega being the wheel's angular velocity,

plus the velocity due to the translation of the center of mass (v = 36 m/s).

The wheel's angular velocity (in radians per second) can be obtained using the tangential velocity for the pure rotational motion and it equals:\omega=\frac{v_t}{r} =\frac{36}{0.25} \,s^{-1}

Then the addition of these two velocities equals:

\omega\,R+v=\frac{36}{0.25} (0.25)\,\,\frac{m}{s} +36\,\,\frac{m}{s} =72\,\,\frac{m}{s}

7 0
3 years ago
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