A ball is projected with initial velocity 50m/s at an angle of elevation of 37 degrees from the top of a cliff 55 m high. Calcul
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Answer:
Explanation:
Given:
- actual weight on the earth, m = 150 lbs × g = 68.0389 kgf
- apparent weight in the spacecraft, M = 175 lbs × g = 79.3787 kgf
∵The apparent weight increases it means that the spacecraft is accelerating in the direction opposite to the gravity and having the value greater than 9.8
DIfference in the weight,
This difference in weight is due to the difference in acceleration of the gravity and the spacecraft.
So, the quantity of acceleration responsible for this difference in weight:
.................(1)
where:
m= mass of the body being accelerated
= difference in the acceleration
from eq. (1)
∴The actual accelerationof the spacecraft:
a=
a = 9.8 + 1.6333
a =