The kinetic energy of an object of mass m moving with speed v is given by:

For the bicycle in our problem,

and

, so the kinetic energy is
The angle of prism is 41.81 degrees.
<u>Explanation:</u>
For no emergence to be taken place, inside a prism, Total Internal Reflection (TIR) should take place at the second surface. For TIR, at second surface, angle of refraction must be greater than critical angle. Angle of prism is related to refraction as,

Since,
= C and 
This implies 



when sin goes to other side become as sin inverse of value, and obtain the result as below,

Explanation:
The given data is as follows.
F = 
q = 
v = 385 m/s
= 0.876
Now, we will calculate the magnitude of magnetic field as follows.
B = 
= 
=
T
= 10.65 T
Thus, we can conclude that magnitude of the magnetic field is 10.65 T.
Answer: 7.38 km
Explanation: The attachment shows the illustration diagram for the question.
The range of the bomb's motion as obtained from the equations of motion,
H = u(y) t + 0.5g(t^2)
U(y) = initial vertical component of velocity = 0 m/s
That means t = √(2H/g)
The horizontal distance covered, R,
R = u(x) t = u(x) √(2H/g)
Where u(x) = the initial horizontal component of the bomb's velocity = 287 m/s, H = vertical height at which the bomb was thrown = 3.24 km = 3240 m, g = acceleration due to gravity = 9.8 m/s2
R = 287 √(2×3240/9.8) = 7380 m = 7.38 km