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Fed [463]
3 years ago
7

6) Consider a 10.0 kg block of wood that's released from rest at a distance 20.0m above the

Physics
1 answer:
tamaranim1 [39]3 years ago
3 0

Explanation:

a) Potential energy is weight times height.

PE = mgh

PE = (10.0 kg) (9.8 m/s²) (20.0 m)

PE = 1960 J

b) Energy is conserved.  As the block falls, potential energy is converted to kinetic energy.  Just before the block lands, all of the potential energy has been converted to kinetic energy.

KE = 1960 J

c) When the block has fallen half the distance, half the potential energy has been converted to kinetic energy.

KE = 1960 J / 2

KE = 980. J

d) Kinetic energy equals half the mass times the square of the velocity.

KE = ½ mv²

980. J = ½ (10.0 kg) v²

v = 14.0 m/s

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A 2.00 kg object is attached to a spring and placed on frictionless, horizontal surface. Ahorizontal force of 18.0 N is required
velikii [3]

Answer:

6 rad/s

Explanation:

In a spring the angular frequency is calculated as follows:

\omega=\sqrt{\frac{k}{m} }

where \omega is the angular frequency, m is the mass of the object in this case m=2kg, and k is the constant of the spring.

To calculate the angular frequency, first we need to find the constant k which is calculated as follows:

k=\frac{F}{x}

Where F is the force: F=18N, and x is the distance from the equilibrium position: x=0.25m.

Thus the spring constant:

k=\frac{18N}{0.25m}

k=72N/m

And now we do have everything necessary to calculate the angular frequency:

\omega=\sqrt{\frac{k}{m} }=\sqrt{\frac{72N/m}{2kg} }=\sqrt{36}

\omega=6rad/s

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4 years ago
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3 years ago
A cylindrical tungsten filament 16.0 cm long with a diameter of 1.00 mm is to be used in a machine for which the temperature wil
KonstantinChe [14]

Answer:

Explanation:

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= \frac{5.25\times10^{-8}\times16\times10^{-2}}{3.14\times(.5\times10^{-3})^2}

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Resistance at 120 degree can be obtained from the following formula

R_t = R_0( 1 + \alpha\times t )

R_t = 107\times10^{-4}( 1 + .0045\times 100)

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current = 12.5

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=  0 .1939 V

= .19 V

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