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ivanzaharov [21]
2 years ago
7

1. A football is kicked with a velocity. of 20m/s at an angle of 45° with the horizontal i. Find the time taken by the ball to s

trike the ground ii. Find the maximum height 11. How far from the kick does it hit the ground Take gravity = 10 m/s​
Physics
1 answer:
dexar [7]2 years ago
6 0

(a) The maximum height reached by the projectile is 10.2 m and

(b) The horizontal distance traveled by the projectile is 40.8 m.

<h3>Maximum height reached by the projectile</h3>

H = u²sin²θ/2g

H = (20²(sin(45))² / (2 x 9.8)

H = 10.2 m

<h3>Time of motion</h3>

T = (2u sinθ)/g

T = (2 x 20 x sin(45) )/(9.8)

T = 2.886 s

<h3>Horizontal distance traveled by the projectile</h3>

x = (v cos(45) x t

x = (20 x cos(45)) x 2.886

x = 40.8 m

Thus, the maximum height reached by the projectile is 10.2 m and the horizontal distance traveled by the projectile is 40.8 m.

Learn more about maximum height here: brainly.com/question/12446886

#SPJ1

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Radar uses radio waves of a wavelength of 2.4 \({\rm m}\) . The time interval for one radiation pulse is 100 times larger than t
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Answer:

120 m

Explanation:

Given:

wavelength 'λ' = 2.4m

pulse width 'τ'= 100T ('T' is the time of one oscillation)

The below inequality express the range of distances to an object that radar can detect

τc/2 < x < Tc/2 ---->eq(1)

Where, τc/2 is the shortest distance

First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'

f = c/λ (c= speed of light i.e 3 x 10^{8} m/s)

f= 3 x 10^{8} / 2.4

f=1.25 x  10^{8} hz.

As, T= 1/f

time of one oscillation T= 1/1.25 x  10^{8}

T= 8 x 10^{-9} s

It was given that pulse width 'τ'= 100T

τ= 100 x 8 x 10^{-9} => 800 x 10^{-9} s

From eq(1), we can conclude that the shortest distance to an object that this radar can detect:

x_{min}= τc/2 =>  (800 x 10^{-9} x 3 x 10^{8})/2

x_{min}=120m

8 0
4 years ago
30. A box with mass 20kg is on a cement floor. The coefficient of static friction between the box and floor is 0.25. A man is pu
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Answer:

84.05

Explanation:

  • F=mg×0.25
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  • f=49.05N
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F=f+F

F=49.05+35

=84.05

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Answer: 3.3 x 10^-28 J

Explanation: just answered on a quiz!! :)

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<u>Answer:</u>

This is due to the apparent movement of the celestial bodies, seen from an observer centered on the Earth. If we did not have knowledge of the advances of science and the latest discoveries, we would think that the Earth is the center of the universe.

For example, for an observer on Earth as a reference system, the Sun moves every day from east to west, as do the planets and all the stars that we observe at night, which leads the observer to believe that those in motion are these bodies outside in the sky while the earth is still and fixed in the universe.

Keep in mind that this theory of geocentrism was widely accepted for a long time in antiquity, until the astronomer Nicolaus Copernicus proposed a completely different and opposite idea, heliocentrism (universe centered on the Sun).

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