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leva [86]
3 years ago
8

30. A box with mass 20kg is on a cement floor. The coefficient of static friction between the box and floor is 0.25. A man is pu

shing the box with a horizontal force of 35N. What is the magnitude of the force of static friction between the box and floor
Physics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

84.05

Explanation:

  • F=mg×0.25
  • F=20x9.81×0.25
  • f=49.05N
  • F=35N

F=f+F

F=49.05+35

=84.05

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on aircraft carriers, catapults are used to accelerate jet air craft to flight speeds in a short distance. One such catapult tak
sineoko [7]

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) - (speed at the beginning)

The jet's change in speed = (70 m/s) - (zero) = 70 m/s

So acceleration = (70 m/s) / (2.5 s)

Acceleration = (70 / 2.5) m/s²

<em>Acceleration = 28 m/s²</em>  

That's about 2.9 G's .  Jet pilots can endure a lot more than that, but maybe the catapult or the hook on the airplane can't.  Let's look a little closer:

F = m A (Newton #2)

The force on the airplane = (18,000 kg) x (28 m/s²)

Force on the airplane = 504,000 Newtons

That's about 113,000 pounds !  Maybe the part of the airplane that the catapult pushes on can't handle any more force than that.  Or maybe that's the most force the catapult can deliver.

Also, the REACTION force on the catapult is the same 113,000 pounds.  Maybe the hooks or the chains or the struts on the catapult can't handle any more force than that.

That's almost 57 tons for gosh sakes !  Maybe the DECK of the carrier can't handle more force than that, and that's why they can't launch the airplane with acceleration of more than 2.9 G's .

8 0
3 years ago
A rain cloud contains 5.32 × 107 kg of water vapor. The acceleration of gravity is 9.81 m/s 2 . How long would it take for a 2.0
Alja [10]

Answer:

20.85 years

Explanation:

2.61 km = 2610 m

2.07 kW = 2070 W

First we need to calculate the potential energy required to take m = 5.32 * 10^7 kg of rain cloud to an altitude of 2610 m is

E = mgh = 5.32 * 10^7 * 9.81 * 2610 = 1.4*10^{12}J

With a P = 2070 W power pump, this can be done within a time frame of

t = E/P = \frac{1.4*10^{12}}{2070} = 658037739 s

or 658037739/(60*60) = 182788 hours or 182788 / 24 = 7616 days or 7616 / 365.25 = 20.85 years

4 0
4 years ago
If a string vibrates at the fundamental frequency of 528 Hz and also produces an overtime with a frequency of 1,056 Hz this over
Romashka-Z-Leto [24]
I have a hunch that you're not talking about overtime
OR overtune.  I think you're going for overtone .

For a fundamental frequency of 528 Hz,
1,056 Hz is the second harmonic.
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3 years ago
Where is visible light located on the electromagnetic spectrum?
nikklg [1K]
2 near the middle
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