Question

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)ΔH°=−57.1kJ/molrxn

Answer 1

Answer:

57.1 kilo Joules of heat would be released.

Explanation:

$HCl(aq)+NaOH(aq)\rightarrow NaCl(aq)+H_2O(l)$ ΔH°=-57.1kJ/mol

Molarity of HCl = 2.00 M

Molarity of NaOH = 1.00 M

According to reaction , 1 M of HCl reacts with 1 M of NaOH. Then 2.00 M of HCl will react with:

$\frac{1}{1}\times 2.00 M= 2M$ of NaOH

But according to question we only have 1.00 M NaOH .So, this means that NaOH is limiting reagent and HCl is an excessive reagent.

Heat evolved will depend upon concentration of NaOH solution :

Heat evolved when 1.00 M of NaOH reacts =

$1.00\times (-57.1 kJ/mol)=-57.1 kJ$

Negative sign means that heat is released during the reaction.

57.1 kilo Joules of heat would be released.