Question

19. If f(x) = 6x + 3, find f-1(x).

Answer 1

Answer:

$f^{-1}$(x) = $\frac{x-3}{6}$

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 6x + 3 ( subtract 3 from both sides )

y - 3 = 6x ( divide both sides by 6 )

$\frac{y-3}{6}$ = x

change y back into terms of x, thus

$f^{-1}$(x) = $\frac{x-3}{6}$