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Nonamiya [84]
3 years ago
13

19. If f(x) = 6x + 3, find f-1(x).

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0

Answer:

f^{-1}(x) = \frac{x-3}{6}

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 6x + 3 ( subtract 3 from both sides )

y - 3 = 6x ( divide both sides by 6 )

\frac{y-3}{6} = x

change y back into terms of x, thus

f^{-1}(x) = \frac{x-3}{6}

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Answer:

D

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the cost of the Joneses new car was $26,000 when rounded to the nearest thousand what is the greatest possible amount the car co
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X=<br> - 6 2/3<br> - 9<br> - 12<br> please help asap
Nastasia [14]

Answer:

Step-by-step explanation:

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4 0
3 years ago
Which of the follwing is true 3 3/9+7 6/11=10 87/99 2 3/8+6 4/5=8 12/40 ,3 3/7+4 2/3=7 2/21 4 5/6+5 5/7=9 10/13
garri49 [273]

Answer: 3 3/9+7 6/11 = 10 87/99

Step-by-step explanation:

a. 3 3/9+7 6/11 = 10 87/99

First and foremost, we need to know the lowest common multiple of 9 and 11 which is 99.

Therefore, 3 3/9 + 7 6/11 would be:

= 3 33/99 + 7 54/99

= 10 87/99

This is correct

b. 2 3/8 + 6 4/5 = 8 12/40

First and foremost, we need to know the lowest common multiple of 8 and 5 which is 40.

Therefore, 2 3/8 + 6 4/5 would be:

= 2 15/40 + 6 32/40

= 8 47/40

= 9 7/40

Since the answer gotten is 8 12/40. This is wrong.

c. 3 3/7 + 4 2/3 = 7 2/21

First and foremost, we need to know the lowest common multiple of 7 and 3 which is 21.

Therefore, 3 3/7 + 4 2/3 would be:

= 3 9/21 + 4 14/21

= 7 23/21

= 8 2/21

Since the answer gotten is 7 2/21. This is wrong.

d. 4 5/6 + 5 5/7 = 9 10/13

First and foremost, we need to know the lowest common multiple of 6 and 7 which is 42.

Therefore, 4 5/6 + 5 5/7 would be:

= 4 35/42 + 5 30/42

= 9 65/42

= 10 23/42

This is wrong as the answer gotten is 9 10/13

Therefore, the true option is

3 3/9+7 6/11 = 10 87/99

7 0
3 years ago
The sum of 2 time a number and -7, added to 5 times the number
DIA [1.3K]

Answer:

7x - 7

Step-by-step explanation:

Variable: X = the unknown number

2x + (-7) + 5x

= 7x - 7

4 0
4 years ago
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