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FinnZ [79.3K]
2 years ago
10

Be sure to answer all parts.

Chemistry
1 answer:
Ede4ka [16]2 years ago
7 0

The Ksp of the solution is 1.97 * 10^-9.

<h3>What is the pH?</h3>

The pH is defined as the hydrogen ion concentration of the solution. Now we have the pH of the solution as 10.9.

We know that;

pOH = 14 - pH

pOH = 14 - 10.9

pOH = 3.1

[OH^-] = Antilog [-3.1]

[OH^-] =7.9 * 10^-4 M

Now

Ksp = [M^2+] [2OH^-]^2

Ksp = s * (2s)^2

Ksp = 4s^3

Now s = 7.9 * 10^-4 M

Ksp = 4(7.9 * 10^-4)^3

Ksp = 1.97 * 10^-9

Learn more about Ksp:brainly.com/question/27132799

#SPJ1

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Assuming that the F−18 can be transported at 59.0 miles/hour, how close must the hospital be to the cyclotron if 68% of the F−18
tekilochka [14]

Answer:

60.12 miles

Explanation:

Using the calculation formula shown below:

t_{1/2} =\frac{t}{[tex]log_{2}\frac{N_{o} }{N_{t} } }[/tex]

where:

t_{1/2} is the half life, N_{o} is the original amount of F-18, and N_{t} is the remaining amount of F-18 at time t.

Generally, F-18 has an half life of 1.83 hours.

Therefore:

t = 1.83*[tex]log_{2}\frac{100}{68} = 1.02 hours[/tex]

Therefore using a speed of 59 miles/hour, the closeness of the hospital is:

distance = speed*time = 59*1.02 = 60.12 miles

6 0
3 years ago
Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.

On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


7 0
4 years ago
If the equilibrium constant for the reaction A 2B C 5/2 D has a value of 4.0, what is the value of the equilibrium constant for
nirvana33 [79]

Answer:

K'=\frac{1}{16}

Explanation:

Hello!

In this case, since the given reaction is:

A+ 2B \rightleftharpoons C+ \frac{5}{2} D

Whereas the equilibrium constant is:

K=\frac{[C][D]^{5/2}}{[A][B]^2} =4.0

However, the new target reaction reverses and doubles the initial reaction to obtain:

2C+5D \rightleftharpoons 2A+4B

Whereas the equilibrium constant is:

K'=\frac{[A]^2[B]^4}{[C]^2[D]^5}

Which suggest the following relationship between the equilibrium constants:

K'=\frac{1}{K^2}

So we plug in to obtain:

K'=\frac{1}{4.0^2}\\\\K'=\frac{1}{16}

Best regards!

8 0
3 years ago
How many atoms are in 1.4 mol of phosphorus trifluoride (PF3)?
joja [24]

Number of atoms in 1.4 mol of Phosphorus trifluoride (PF₃) : 8.428 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.4 mol of Phosphorus trifluoride (PF₃), number of atoms :

\tt N=1.4\times 6.02\times 10^{23}\\\\N=8.428\times 10^{23}

5 0
3 years ago
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Vlada [557]

Answer:

Los hongos, a diferencia de las plantas que utilizan la fotosíntesis para producir su alimento, absorben los nutrientes de materia orgánica que descomponen.

Explanation:

8 0
3 years ago
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