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2 years ago

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Chemistry

1 answer:

Ede4ka [16]2 years ago

7 0

The Ksp of the solution is 1.97 * 10^-9.

The pH is defined as the hydrogen ion concentration of the solution. Now we have the pH of the solution as 10.9.

We know that;

pOH = 14 - pH

pOH = 14 - 10.9

pOH = 3.1

[OH^-] = Antilog [-3.1]

[OH^-] =7.9 * 10^-4 M

Now

Ksp = [M^2+] [2OH^-]^2

Ksp = s * (2s)^2

Ksp = 4s^3

Now s = 7.9 * 10^-4 M

Ksp = 4(7.9 * 10^-4)^3

Ksp = 1.97 * 10^-9

Learn more about Ksp:brainly.com/question/27132799

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Answer: The maximum amount of water that can be produced is 0.74 g

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid:}=\frac{1.5g}{36.5g/mol}=0.041mol$

$\text{Moles of sodium hydroxide}=\frac{2.67g}{40g/mol}=0.067mol$

The chemical equation for the reaction is

$HCl+NaOH\rightarrow NaCl+H_2O$

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of NaOH

So, 0.041 moles of HCl will react with = $\frac{1}{1}\times 0.041=0.041mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent. Thus, HCl is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of HCl produces = 1 mole of water

So, 0.041 moles of HCl will produce = $\frac{1}{1}\times 0.041=0.041moles$ of water

Mass of water= $moles\times {\text{Molar Mass}}=0.041mol\times 18g/mol=0.74g$

Thus the maximum amount of water that can be produced is 0.74 g

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3 years ago

One mole of carbon (12.0 g) in the form of crystalline graphite is burned at 25◦C and 1.000 atm pressure to form CO2(g). All of

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Answer:

T₂ = 43.46 °C

Explanation:

Given that:

The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)

It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J

Heat gain by water = Heat lost by the reaction

Thus,

$m_{water}\times C_{water}\times \Delta T=Q$

For water:

Mass of water = 5100 g

Specific heat of water = 4.18 J/g°C

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T₂ = ?

Q = 393500 J

So,

$5100\times 4.18\times (T_2-25)=393500$

T₂ = 43.46 °C

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3 years ago

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Answer:

True.

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The Hund's Rule states that all orbitals must be singled occupied before any orbital is doubly occupied, and all the electrons at the singly occupied orbitals have the same spin number. By doing that, the electrons filled the lowest energy orbitals first.

The 2p level has 3 orbitals: 2px, 2py, and 2pz. So, when filling it, first put an electron in the 2px, then in the 2py, then and the 2pz (all with the same spin). After that, the remains electrons can be paired up.

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3 years ago

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Answer:

2071g or 2.071kg of rust (Fe3O4)

Explanation:

Step 1:

The balanced equation for the reaction.

3Fe + 4H2O —> Fe3O4 + 4H2

Step 2:

Determination of the mass of Fe that reacted and the mass of the Fe3O4 produced from the balanced equation.

Molar Mass of Fe = 56g/mol

Mass of Fe from the balanced equation = 3 x 56 = 168g

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Mass of Fe3O4 from the balanced equation = 1 x 232 = 232g

Summary:

From the balanced equation above,

168g of Fe reacted and 232g of Fe3O4 was produced.

Step 3:

Determination of the mass of rust (Fe3O4) produced when 1.5kg ( i.e 1500g) of Fe reacted.

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From the balanced equation above,

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