Answer:
60.12 miles
Explanation:
Using the calculation formula shown below:
\frac{N_{o} }{N_{t} } }[/tex]
where:
is the half life,
is the original amount of F-18, and
is the remaining amount of F-18 at time t.
Generally, F-18 has an half life of 1.83 hours.
Therefore:
\frac{100}{68} = 1.02 hours[/tex]
Therefore using a speed of 59 miles/hour, the closeness of the hospital is:
distance = speed*time = 59*1.02 = 60.12 miles
Above question is incomplete. Complete question is attached below
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Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case,
reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is
least reactive.
On other hand,
reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is
most reactive.
Answer:

Explanation:
Hello!
In this case, since the given reaction is:

Whereas the equilibrium constant is:
![K=\frac{[C][D]^{5/2}}{[A][B]^2} =4.0](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BC%5D%5BD%5D%5E%7B5%2F2%7D%7D%7B%5BA%5D%5BB%5D%5E2%7D%20%3D4.0)
However, the new target reaction reverses and doubles the initial reaction to obtain:

Whereas the equilibrium constant is:
![K'=\frac{[A]^2[B]^4}{[C]^2[D]^5}](https://tex.z-dn.net/?f=K%27%3D%5Cfrac%7B%5BA%5D%5E2%5BB%5D%5E4%7D%7B%5BC%5D%5E2%5BD%5D%5E5%7D)
Which suggest the following relationship between the equilibrium constants:

So we plug in to obtain:

Best regards!
Number of atoms in 1.4 mol of Phosphorus trifluoride (PF₃) : 8.428 x 10²³
<h3>Further explanation </h3>
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
1.4 mol of Phosphorus trifluoride (PF₃), number of atoms :

Answer:
Los hongos, a diferencia de las plantas que utilizan la fotosíntesis para producir su alimento, absorben los nutrientes de materia orgánica que descomponen.
Explanation: