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Levart [38]
3 years ago
11

According to Hund's Rule, if you were filling the three orbitals at the 2p energy level, you would first put an electron in the

2px orbital, then in the 2py orbital , and then in the 2pz orbital; and THEN use any additional electrons to pair up (one at a time) with those electrons.
A. True
B. False
Chemistry
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

True.

Explanation:

The Hund's Rule states that all orbitals must be singled occupied before any orbital is doubly occupied, and all the electrons at the singly occupied orbitals have the same spin number. By doing that, the electrons filled the lowest energy orbitals first.

The 2p level has 3 orbitals: 2px, 2py, and 2pz. So, when filling it, first put an electron in the 2px, then in the 2py, then and the 2pz (all with the same spin). After that, the remains electrons can be paired up.

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If the aluminum block is initially at 25 ∘C, what is the final temperature of the block after the evaporation of the alcohol? As
skad [1K]

Explanation:

The given data is as follows.

       Heat of vaporization (\Delta H_{vap}) = 45.4 kJ/mol

       Specific heat (C_{p}) = 0.903 j/g^{o}C

Let us assume the alcohol given is C_{3}H_{8}O and its mass is 1.12 g. Also, mass of aluminium block is 73.0 g.

First, calculate the moles of alcohol (C_{3}H_{8}O) as follows.

          No. of moles alcohol = \frac{mass}{\text{molar mass}}

                                              = \frac{1.12 g}{60.1 g/mol}

                                              = 0.0186 mol

So, heat absorbed by the alcohol (q_{alcohol}) = heat lost by aluminium (q_{aluminium})

          n \times \Delta H_{vap} = -m \times C_{p} \times \Delta T

          0.0186 mol \times 45.4 kJ/mol = - 73.0 g \times 0.903 J/g^{o}C \times (T_{f} - 25^{o}C)

              12.71 = - (T_{f} - 25^{o}C)

                   T_{f} = 12.3^{o}C

Thus, we can conclude that the final temperature of the block is 12.3^{o}C[/tex].

7 0
3 years ago
A 90 lb person is prescribed a drug in the amount of 50mg/kg body per day to be delivered in 2 doses per day. Each tablet contai
geniusboy [140]

Answer:

4 tabletes/dose

Explanation:

mass person = (90 Lb)×(Kg/2.20462 Lb) = 40.823 Kg body

amount of medicine = 50 mg/Kg body.day

frecuency = 2 dose/day

⇒ amount of medicine/day =  (50 mg/kg body.day)×(40.823 Kg body) = 2041.168 mg/day

⇒ mg medicine/dose = (20141.168 mg/day)×(day/ 2 dose) = 1020.584 mg medicine/dose

∴ mg medicine/tablet = 250 mg medicine/tablet

⇒ # tabletes/dose = (1020.584 mg medicine/dose)×(tablet/250 mg medicine) = 4.082 tabletes/dose

⇒ # tabletes/dose ≅ 4 tabletes/dose

7 0
2 years ago
What is the color of the flame when magnesium burns in air ​
vfiekz [6]

Answer:

Will u give me brainliest

white

In its pure form, it is silvery white, and relatively soft. It burns in air with a brilliant white light, and for this reason is often used in flares and fireworks. Magnesium is used in disposable flash bulbs to generate light for photography, but this use has been largely supplanted by other sources of illumination

6 0
2 years ago
Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of c
Anna [14]

The question is incomplete. The complete question is

Two solutions are combined in a beaker. One solution contains 500.0 g of potassium phosphate and the other contains 500.0 g of calcium nitrate. A double displacement reaction occurs. What mass of each of the following substances is present when the reaction stops. A) potassium phosphate remaining B) calcium nitrate g remaining C) calcium phosphate formed D) potassium nitrate g formed

Answer:

a)84.91g

b)8.20g

c)316.4g

d)616.73g

Explanation:

The equation of the reaction:

2K3PO4(aq) + 3Ca(NO3)2 (aq)-------> 6KNO3(aq) + Ca3(PO4)2(s)

Molar mass of potassium phosphate= 212.27 g/mol

Amount of potassium phosphate= 500/212.27= 2.4 moles

Molar mass of calcium nitrate= 164.088 g/mol

Amount of calcium nitrate= 500/164.088=3.05moles

a) amount of potassium phosphate reacted according to reaction equation= 2 moles

Amount of potassium phosphate remaining= 2.4-2=0.4 moles

Mass of potassium phosphate remaining= 0.4×212.27=84.91g

b) Amount of calcium nitrate reacted according to reaction equation=3

Amount of calcium nitrate remaining=3.05-3= 0.05

Mass of calcium nitrate remaining= 0.05×164.088= 8.20g

c) since calcium nitrate is the limiting reactant, we use to estimate the mass of products formed.

From the reaction equation,

3 moles of calcium nitrate yields 1 mole of calcium phosphate

3.05 moles of calcium nitrate yields 3.05/3 = 1.02 moles of calcium phosphate

Molar Mass of calcium phosphate= 310.18 g/mol

Mass of calcium phosphate produced= 1.02×310.18= 316.4g

d)

3 moles of calcium nitrate yields 6 moles of potassium nitrate

3.05 moles of calcium nitrate yields 3.05×6/3= 6.1 moles of potassium nitrate

Molar mass of potassium nitrate = 101.1032 g/mol

Mass of potassium nitrate formed= 6.1× 101.1032= 616.73g

6 0
3 years ago
2. As NH4OH is added to an HCl solution, the pH of the solution
chubhunter [2.5K]

Answer:

c

Explanation:

Nh4OH + HCL ---> NH4Cl + H3O

so ph decreases as H3O increases

and OH also decreases

5 0
2 years ago
Read 2 more answers
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