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andreev551 [17]
2 years ago
8

Zns (zinc sulfide) (Zn = 65.38; S = 32.06] *

Chemistry
1 answer:
irakobra [83]2 years ago
3 0

The question is incomplete, the complete question is;

Zinc and sulfur react to form zinc sulfide by the equation shown below. How many grams of ZnS can be formed when 12.0 g of Zn reacts with 6.50 g of S? (Atomic mass: Zn = 65.38, S = 32.06).

Answer:

17.5 g of ZNS

Explanation:

The equation of the reaction is;

Zn(s) + S(s) ------->ZnS(s)

Number of moles of Zn = 12.0/65.38 = 0.18 moles

Number of moles of S = 6.50/32.06 = 0.20 moles

Hence Zn is the limiting reactant

If 1 mole of Zn yields 1 mole of ZnS

Then 0.18 moles of Zn also yields 0.18 moles of ZnS

Mass of ZnS produced = 0.18 moles *  97.44 g/mol = 17.5 g of ZNS

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The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?
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Answer : The volume of pure diamond is 0.493inch^3

Explanation : Given,

Density of pure carbon in diamond = 3.52g/cm^3

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Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}

Molar mass of carbon = 12 g/mol

\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g

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Formula used:

Density=\frac{Mass}{Volume}

Now putting all the given values in this formula, we get:

3.52g/cm^3=\frac{284.4g}{Volume}

Volume = 80.8cm^3

As we know that:

1cm^3=0.061inch^3

So,

Volume = 0.061\times 80.8inch^3

Volume = 0.493inch^3

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5 0
3 years ago
A 2 L container contains 5 moles of helium gas at 0.5 atm. What is the<br> temperature of the gas?
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T = ?

Substituting for T in the equation, we obtain:

T = P V / nR

T = 0.5 * 2 / 5 * 0.082

T = 1 / 0.41

T = 2.44 K

The temperature of the gas is 2.44 K

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