All categories

2 years ago

Zns (zinc sulfide) (Zn = 65.38; S = 32.06] *

Chemistry

1 answer:

irakobra [83]2 years ago

3 0

The question is incomplete, the complete question is;

Zinc and sulfur react to form zinc sulfide by the equation shown below. How many grams of ZnS can be formed when 12.0 g of Zn reacts with 6.50 g of S? (Atomic mass: Zn = 65.38, S = 32.06).

Answer:

17.5 g of ZNS

Explanation:

The equation of the reaction is;

Zn(s) + S(s) ------->ZnS(s)

Number of moles of Zn = 12.0/65.38 = 0.18 moles

Number of moles of S = 6.50/32.06 = 0.20 moles

Hence Zn is the limiting reactant

If 1 mole of Zn yields 1 mole of ZnS

Then 0.18 moles of Zn also yields 0.18 moles of ZnS

Mass of ZnS produced = 0.18 moles * 97.44 g/mol = 17.5 g of ZNS

You might be interested in

Rontloc pestu (Scrambled word)

lianna [129]

Is it "control setup"?

5 0

3 years ago

Read 2 more answers

What is true of neutrons?

Marrrta [24]

Neutron, neutral subatomic particle that is a constituent of every atomic nucleus except ordinary hydrogen. It has no electric charge and a rest mass equal to 1.67493 × 10−27 kg—marginally greater than that of the proton but nearly 1,839 times greater than that of the electron.

7 0

3 years ago

Consider the following reaction: CO(g)+2H2(g)⇌CH3OH(g) Kp=2.26×104 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under eac

valentinak56 [21]

Answer : The value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

Explanation :

The formula used for $\Delta G_{rxn}$ is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy

R = gas constant = 8.314 J/mole.K

T = temperature = $25^oC=273+25=298K$

Q = reaction quotient

First we have to calculate the $\Delta G_^o$ .

Formula used :

$\Delta G^o=-RT\times \ln K_p$

Now put all the given values in this formula, we get:

$\Delta G^o=-(8.314J/mole.K)\times (298K)\times \ln (2.26\times 10^{4})$

$\Delta G^o=-24839.406J/mole=-24.83\times 10^3J/mole=-24.83kJ/mole$

Now we have to calculate the value of 'Q'.

The given balanced chemical reaction is,

$CO(g)+2H_2(g)\rightarrow CH_3OH(g)$

The expression for reaction quotient will be :

$Q=\frac{(p_{CH_3OH})}{(p_{CO})\times (p_{H_2})^2}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(1.4)}{(1.2\times 10^{-2})\times (1.2\times 10^{-2})^2}$

$Q=8.1\times 10^{5}$

Now we have to calculate the value of $\Delta G_{rxn}$ by using relation (1).

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

Now put all the given values in this formula, we get:

$\Delta G_{rxn}=-24.83kJ/mole+(8.314\times 10^{-3}kJ/mole.K)\times (298K)\ln (8.1\times 10^{5})$

$\Delta G_{rxn}=8.867\times 10^3J/mole=8.867kJ/mole$

Therefore, the value of $\Delta G_{rxn}$ is, $8.867kJ/mole$

3 0

3 years ago

Where are Uranium and plutonium found? (IN NATURE)

Basile [38]

Wanted to write more both there is a problem with the editor. Uranium is formed naturally in the crust of rocks and seawater. Plutonium does not occur in nature. It is found in the biosphere.

8 0

2 years ago

Read 2 more answers

Which of the following is the strongest base? ta) CH,ONa (b) NaNH, (c) CH-CH,Li (0) NaOH (6) CHÚCONa

Mashutka [201]

Hey there:

Correct answer is :

(b) NaNH₂

Sodium azanide NaNH₂ is the conjugate base of ammonia NH₃

Correct answer is :

(b) NaNH₂

I hope this will help !

7 0

3 years ago