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Vladimir79 [104]
3 years ago
10

Riddles, I speak without a mouth and hear without ears. I have no body, but I come alive with wind. What am I? Answer will be to

ld after you guess.
Chemistry
2 answers:
dedylja [7]3 years ago
7 0

Answer:

An echo speaks without a mouth and hears without ears. It comes alive with wind. Hence, 'An echo' is the required answer to this riddle.

Explanation:

that's so easy i know that 1

Elza [17]3 years ago
4 0

Answer:

Jesus

Explanation:

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14. An increase in temperature results in an increase in ...
shusha [124]

Answer: its C. and B.

Explanation:

hopes this helps

3 0
2 years ago
A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
2 years ago
The substances present before a chemical reaction takes place are called?
andrew11 [14]
The substances present before the reaction are the reactants.  (As the reaction goes through, the substances that are produced are called the products of the reaction).
5 0
3 years ago
Read 2 more answers
Rank the following from highest to lowest priority according to the Cahn-Ingold-Prelog system: -CH2CH3, -CHCH2, -CCH, -CH3.
mario62 [17]

Answer:

The order will be:

CCH > CHCH₂ > CH₂CH₃> CH₃

Explanation:

According to Cahn-Ingold-Prelog system we rank the groups based on the atomic number of directly attached atom with the chiral carbon.

For example: between C and H, we rank Carbon first.

If the same atoms are attached for different groups then we prioritized based on the second element with highest atomic number.

For example:

Among CH₃ and C₂H₅, the priority will be given to C₂H₅.

If an atom is double or triple bonded to the directly attached atom then each pi bond is considered to be a new atom.

Hence CH=CH₂ means, that there are two carbons attached to CH carbon.

So the order based on above selection rules will be:

CCH > CHCH₂ > CH₂CH₃> CH₃

7 0
3 years ago
Will reward brainliest<br> Explain why all arrhenius acids can be considered bronsted lowry acids
GuDViN [60]

Answer:

Explanation:

A bronsted lowry acid just means that it donates a proton.

An arrhenius acid dissolves in water to donate a proton

the only difference is that an arrhenius acid must dissolve in water but it still donates a proton so it is considered a bronsted lowry acid

3 0
2 years ago
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