Answer:
Multiply the top equation by -3 and the bottom equation by 2
Step-by-step explanation:
Given <u>system of equations</u>:

To solve the given system of equations by addition, make one of the variables in both equations <u>sum to zero</u>. To do this, the chosen variable must have the <u>same coefficient</u>, but it should be <u>negative</u> in one equation and <u>positive</u> in the other, so that when the two equations are added together, the variable is <u>eliminated</u>.
<u>To eliminate the </u><u>variable y</u>:
Multiply the top equation by -3 to make the coefficient of the y variable 6:

Multiply the bottom equation by 2 to make the coefficient of the y variable -6:

Add the two equations together to <u>eliminate y</u>:

<u>Solve</u> for x:


<u>Substitute</u> the found value of x into one of the equations and <u>solve for y</u>:





Learn more about systems of equations here:
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Answer:
1/12
Step-by-step explanation:
multiple of 3 and a multiple of 4 implies it can only be 12.
Since you only have the numbers from 1 to 12,
the prob(the 12) = 1/12
Answer:
x = -6
Step-by-step explanation:
Combine like terms.
5x + 6 = -24
Subtract 6 from both sides.
5x = -30
Divide by 5 on both sides.
x = -6
Answer:
0.286
Hope that helps!
Step-by-step explanation:
Answer:
The roots are;
x = (2 + i)/5 or (2-i)/5
where the term i is the complex number representing the square root of -1
Step-by-step explanation:
Here, we want to use the completing the square method to solve the quadratic equation;
f(x) = -5x^2 + 4x -1
Set the function to zero
0 = -5x^2 + 4x - 1
So;
-5x^2 + 4x = 1
divide through by the coefficient of x which is -5
x^2 - 4/5x = -1/5
We now take half of the coefficient of x and square it
= -2/5^2 = 4/25
add it to both sides
x^2 - 4x/5 + 4/25= -1/5 + 4/25
(x- 2/5)^2 = -1/5 + 4/25
(x - 2/5)^2 = -1/25
Take the square root of both sides
x - 2/5 = √( -1/25
x - 2/5 = +i/5 or -i/5
x = 2/5 + i/5 or 2/5 - i/5