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Aneli [31]
1 year ago
5

Cyclohexene oxidation with potassium permanganate gives three different products, depending on conditions. what product (one) co

uld not be obtained
Chemistry
1 answer:
Serhud [2]1 year ago
6 0

Answer:

will you help us with that one please

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How an ionic compound made up of charged particles can be electrically neutral
finlep [7]

Answer:

Explanation:

Ionic compounds are electrically neutral because the charges of the cations and anions that make up the compound cancel each other out. In the case of salt for example, sodium has a charge of positive one, and chloride has a charge of negative one. Together, they neutralize the compound.

5 0
3 years ago
For 30 points! Please help me understand this question
oksian1 [2.3K]

Answer:

D) Adding a catalyst

Explanation:

Adding a catalyst decreases activation energy and allows the reaction to occur more easily.

7 0
3 years ago
G8_SCIENCE_BSA_21_22
S_A_V [24]

Answer:

Explanation: Over the course of a year, areas near Earth’s equator receive more direct energy from the Sun than areas near Earth’s poles.  Which of the following correctly describes one result of this heating pattern?


8 0
2 years ago
La formula estructural del eter butil pentilico
Mama L [17]

Answer:

do you mean?

Explanation:

the structural formula of butyl pentyl ether

3 0
3 years ago
A mixture contains NaHCO3 together with unreactive components. A 1.75 g sample of the mixture reacts with HA to produce 0.561 g
Lynna [10]

Answer:

\%NaHCO_3=61.2\%

Explanation:

Hello.

In this case, since the undergoing chemical reaction is only between the sodium bicarbonate and the acid HA:

NaHCO_3+HA\rightarrow NaA+H_2O+CO_2

For 0.561 g of yielded carbon dioxide (molar mass 44 g/mol), the following mass of sodium bicarbonate (molar mass 84 g/mol) that reacted was:

m_{NaHCO_3}=0.561gCO_2*\frac{1molCO_2}{44gCO_2} *\frac{1molNaHCO_3}{1molCO_2} *\frac{84gNaHCO_3}{1molNaHCO_3} \\\\m_{NaHCO_3}=1.071g

Considering the 1:1 mole ratio between CO2 and NaHCO3. Finally, the percent by mass of NaHCO3 is computed by dividing the mass of reacted NaHCO3 and t the mixture:

\%NaHCO_3=\frac{1.071g}{1.75g}*100\%\\ \\\%NaHCO_3=61.2\%

Best regards.

5 0
3 years ago
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