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4 years ago

12

Whyyyyyy you do this to meeeee I’m soo sad that I Can’t talk to my best friend on Brainly.com

1 answer:

PIT_PIT [208]4 years ago

7 0

Answer:

right

Explanation:

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During the light-independent reaction, carbon dioxide is fixed by adding it to a A. 2-carbon compound B. 3-carbon compound C. 4-

Scrat [10]

During the light independent reaction, carbon dioxide is fixed by adding it to a <span>5-carbon compound</span>

8 0

3 years ago

Read 2 more answers

I NEED HELP PLS! Do the fossil finds in Antarctica support Wegener’s continental drift hypothesis? Explain your answer using exa

romanna [79]

Answer:

There are many examples of fossils found on separate continents and nowhere else, suggesting the continents were once joined. If Continental Drift had not occurred, the alternative explanations would be: The species evolved independently on separate continents – contradicting Darwin's theory of evolution.

hope this helps you ☺️☺️

8 0

3 years ago

What is the name of the compound NiC03 * 8H20?

Hoochie [10]

The answer is :

Nickel II carbonate octahydrate

The explanation:

-when Ni is the symbol of Nickel.

and CO3 is the symbol of carbonate group.

and both have 2 valence so, it will be write 2:2 = 1:1 → NiCO3 named Nickel caronae.

and any compound contain H2O will be named Hydrate and here we have 8 H2O so, i will e named octa (because of his 8 ) octahydrate

so, the compound will be Nickel II carbonate octahydrate

5 0

3 years ago

How many grams of solid sodium cyanide should be added to 1.00 L of a 0.119 M hydrocyanic acid solution to prepare a buffer with

Zepler [3.9K]

Answer:

1.62 g

Explanation:

Given that:

Concentration of HCN = 0.119 M

Assuming the ka 4.00 × 10⁻¹⁰

The pKa of HCN (hydrocyanic acid) = -log (Ka)

= - log ( 4.00 × 10⁻¹⁰)

= 9.398

pH of buffer = 8.809

Using Henderson Hasselbach equation:

$pH = pKa + log \dfrac{[conjugate\ base ]}{acid}$

$pH = pKa + log \dfrac{[CN^-]}{[HCN]}$

$8.809 = 9.398 +log \dfrac{[CN^-]}{[HCN]}$

$log \dfrac{[CN^-]}{[HCN]}= 8.809 - 9.398$

$log \dfrac{[CN^-]}{[HCN]}= -0.589$

$\dfrac{[CN^-]}{[HCN]}= 0.2576$

[CN^-] = 0.2576[HCN]

[CN^-] = 0.2756 (0.119) L

[CN^-] = 0.033 M

∴

The amount of NaCN (sodium cyanide) is calculated as follows:

$= 1.00 L \times \dfrac{0.033 \ mol \ NacN }{1 \ L } \times \dfrac{49.01 \ g}{1 \ mol \ of \ NacN}$

= 1.62 g

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3 years ago

What is a photon?

Anika [276]

The Answer should be A Light particle

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3 years ago