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3 years ago

15

Which is produced in a synthesis reaction?

2 answers:

Rama09 [41]3 years ago

5 0

Answer:

a single compound

Explanation:

which is produced in a synthesis reaction

NISA [10]3 years ago

4 0

Answer:

a single compound

Explanation:

just checked <3

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PLEASE ANSWER THIS QUESTION ASAP.

Natali5045456 [20]

Equal is the answer

Hope this helps

6 0

2 years ago

Read 2 more answers

How many grams of CO2 evolved from a 1.205g sample that is 36% MgCO3 and 44% K2CO3 by mass?

emmasim [6.3K]

Mass of CO₂ evolved : 0.108 g

<h3>Further explanation</h3>

Given

1.205g sample, 36% MgCO3 and 44% K2CO3

Required

mass of CO2

Solution

mass of MgCO₃ :

0.36 x 1.205 g=0.4338 g

mass C in MgCO₃(MW MgCO₃=84 g/mol, Ar C = 12/gmol)

= (12/84) x 0.4338

= 0.062 g

mass of K₂CO₃ :

0.44 x 1.205 g = 0.5302 g

Mass C in K₂CO₃(MW=138 g/mol) :

= (12/138) x 0.5302

= 0.046 g

Total mass Of CO₂ :

= 0.062 + 0.046

= 0.108 g

7 0

3 years ago

How many milliliters of an aqueous solution of 0.170 M ammonium carbonate is needed to obtain 16.1 grams of the salt

Citrus2011 [14]

There will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.There will be needed mL of

Why?

In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:

$(NH_{4})2CO_{3}$

Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:

$N_{2}=14g*2=28g\\\\2H_{4}=2*1g*4=8g\\\\C=12.01g*1=12.01g\\\\O_{3}=15.99g*3=47.97g$

We have that the molecular mass of the substance will be:

$MolecularMass=\frac{28g+8g+12.01g+47.97g}{mol}=95.98\frac{g}{mol}$

Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:

$mol_{(NH_{4})2CO_{3}=\frac{mass_{(NH_{4})2CO_{3}}}{molarmass_{(NH_{4})2CO_{3}}}$

$mol_{(NH_{4})2CO_{3}=\frac{16.1g}{95.98\frac{g}{mol}}=0.167mol$

Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:

$M=\frac{moles_{solute}}{volume_{solution}}$

$M=\frac{moles_{solute}}{volume_{solution}}\\\\volume_{solution}=\frac{moles_{solute}}{M}$

Now, substituting and calculating, we have:

$volume_{solution}=\frac{0.167mol}{0.170\frac{mol}{L}}\\\\volume_{solution}=0.982L=0.982L*1000=982.35mL$

Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.

Have a nice day!

5 0

3 years ago

What amount of carbon dioxide (in moles) is produced from the reaction of 2.24 moles of ethanol with excess oxygen?

algol13

Answer : The amount of carbon dioxide produced is, 197.12 grams.

Explanation : Given,

Moles of ethanol = 2.24 mole

Molar mass of carbon dioxide = 44 g/mole

The balanced chemical reaction will be,

$C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O$

First we have to calculate the moles carbon dioxide.

From the balanced chemical reaction, we conclude that

As, 1 mole of ethanol react to give 2 moles of carbon dioxide

So, 2.24 mole of ethanol react to give $2\times 2.24=4.48$ moles of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

$\text{Mass of }CO_2=\text{Moles of }CO_2\times \text{Molar mass of }CO_2$

$\text{Mass of }CO_2=4.48mole\times 44g/mole=197.12g$

Therefore, the amount of carbon dioxide produced is 197.12 grams.

8 0

2 years ago

When 120 g of carbon reacts completely with 320 g of oxygen the mass of carbon dioxide formed will be?

olga2289 [7]

440 cause mass cant be created or destroyed

6 0

3 years ago