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Ainat [17]
3 years ago
11

Compare the two types of optical telescopes

Chemistry
1 answer:
Jet001 [13]3 years ago
3 0

Answer: Reflectors use a mirror to collect the light, whilst refractors use a lens while, Refractor telescopes require a large lens at the front to direct the incoming light to the lens.

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Convert 3828 ml to L
crimeas [40]

Answer:

divide the volume value by 1000

So 3828/1000=3.828

3 0
3 years ago
An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 2.50g of this compound produced 3.67g of
REY [17]
The solution to the problem is as follows:

 <span>a) 

C + O2 = CO2 

Molar mass CO2 = 44 g/mol 

3.67 g CO2 * 1 mol / 44 g = 

=0.0834 mol CO2 = 0.0834 mol C 

I hope my answer has come to your help. God bless and have a nice day ahead!
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4 0
3 years ago
When strongly electronegative atoms, like fluorine, bond to atoms with a lower electronegativity, like hydrogen, what's the resu
olganol [36]
When highly electronegative element like oxygen is directly attached to less electronegative element like hydrogen the electrons from less electronegative elements are attracted toward the highly electronegative element, making the less electronegative element deficient in electron density (partial positive) and a partial negative charge on more electronegative element is created. In such situation the intermolecular forces formed are dipole-dipole interactions or hydrogen bond interaction like in HF.
7 0
3 years ago
A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As
TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

P.V=n.R.T=\frac{m}{M} .R.T

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g

7 0
3 years ago
(100 points) Imagine that the ability to cool materials down to below 200 K (–100° F) was not discovered until 1950. Which techn
umka2103 [35]

Answer: (D) Superconductivity

Explanation: Edge 2021

4 0
3 years ago
Read 2 more answers
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