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3 years ago

Compare the two types of optical telescopes

1 answer:

3 0

Answer: Reflectors use a mirror to collect the light, whilst refractors use a lens while, Refractor telescopes require a large lens at the front to direct the incoming light to the lens.

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how would a chemical reaction that includes an enzyme differ from a chemical reaction that thats places without an enzyme

alukav5142 [94]

Enzymes offer a faster pathway for the reaction to happen, so they lower the activation energy necessary for the reaction to happen. The result is that the reaction will happen faster

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3 years ago

In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure

kirill [66]

Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to Dalton's Law of Partial Pressure the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

$P_{total}= P_1+P_2+P_3+\dots +P_n$

Here ,

Partial pressure of Gas A = 400mm of Hg
Partial pressure of Gas B = 220 mm of Hg
Partial pressure of Gas C = 140mm of Hg

Hence the total pressure exerted is ,

$P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }$

Substitute ,

$P_{total}=( 400 + 220 + 140 )mm\ of \ Hg$

Add ,

$P_{total}= 760\ mm\ of \ Hg$

Hence the total pressure exerted by the gases is 760 mm of Hg.

I hope this helps.

4 0

2 years ago

PLZ HELLLLPPPP

coldgirl [10]

D. The nucleus is the control center of the cell

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3 years ago

What is the frequency of radiation.

Ivenika [448]

RADIATION. Radio waves, microwaves, IR, light, UV, x-rays, GAMMA waves etc are ALL Electromagnetic radiation. The difference between ALL the above is the frequency, I.E. The number of waves per second. The higher the frequency the more energy.

5 0

3 years ago

A sample of 23.2 g of nitrogen gas is reacted with

slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0

3 years ago