1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WINSTONCH [101]
2 years ago
9

MATH PERCENTAGE QUESTION HELP!

Mathematics
1 answer:
lubasha [3.4K]2 years ago
8 0

Answer:

68.5% seats filled

76% points earned

Step-by-step explanation:

<h3><u>General outline</u></h3>
  1. Identify the whole and the part
  2. Change ratio into a percentage

<h3><u>Ratios</u></h3>

Percentages are formed when one finds a ratio of two related quantities, usually comparing the first partial quantity to the amount that "should" be there.

\text{ratio}=\dfrac {\text{the "part"}}{\text{the whole}}

For instance, if you have a pie, and you eat half of the pie, you're in effect imagining the original pie (the whole pie) cut into two equal pieces, and you ate one of them (the "part" of a pie that you ate).  To find the ratio of pie that you ate compared to the whole pie, we compare the part and the whole:

\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}

\text{ratio}=\dfrac {1}{2}

If you had instead eaten three-quarters of the pie, you're in effect imagining the original pie cut into 4 equal pieces, and you ate 3 of them.

\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}

\text{ratio}=\dfrac {3}{4}

There can be cases where the "part" is bigger than the whole.  Suppose that you are baking pies and we want to find the ratio of the pies baked to the number that were needed, the number of pies you baked is the "part", and the number of pies needed is the whole.  This could be thought of as the ratio of project completion.

If we need to bake 100 pies, and so far you have only baked 75, then our ratio is:

\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}

\text{ratio}=\dfrac {75}{100}

But, suppose you keep baking pies and later you have accidentally made more than the 100 total pies.... you've actually made 125 pies.  Even though it's the bigger number, the number of pies you baked is still the "part" (even though it's bigger), and the number of pies needed is the whole.

\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}

\text{ratio}=\dfrac {125}{100}

<h3><u>Percentages</u></h3>

To find a percentage from a ratio, there are two small steps:

  1. Divide the two numbers
  2. Multiply that result by 100 to convert to a percentage

<u>Going back to the pies:</u>

When you ate half of the pie, your ratio of pie eaten was \frac{1}{2}

Dividing the two numbers, the result is 0.5

Multiplying by 100 gives 50.  So, the percentage of pie that you ate (if you ate half of the pie) is 50%

When you ate three-quarters of the pie, the ratio was \frac{3}{4}

Dividing the two numbers, the result is 0.75

Multiplying by 100 gives 75.  So, the percentage of pie that you ate (if you ate three-quarters of the pie) is 75%.

When you were making pies, and 100 pies were needed, but so far you'd only baked 75 pies, the ratio was \frac{75}{100}

Dividing the two numbers, the result is 0.75

Multiplying by 100 gives 75.  So, the percentage of the project that you've completed at that point is 75%.

Later, when you had made 125 pies, but only 100 pies were needed, the ratio was \frac{125}{100}

Dividing the two numbers, the result is 1.25

Multiplying by 100 gives 125%.  So, the percentage of pies you've made to complete the project at that point is 125%.... the number of pies that you've made is more than what you needed, so the baking project is more than 100% complete.

<h3><u>The questions</u></h3>

<u>1.   27400 spectators n a 40000 seat stadium percentage.</u>

Here, it seems that the question is asking what percentage of the stadium is full, so the whole is the 40000 seats available, and the "part" is the 27400 spectators that have come to fill those seats.

\text{ratio}=\dfrac {\text{the number of spectators filling seats}}{\text{the total number of seats in the stadium}}

\text{ratio}=\dfrac {27400}{40000}

Dividing gives 0.685.  Multiplying by 100 gives 68.5.  So, 68.5% of the seats have been filled.

<u>2.   an archer scores 95 points out of a possible 125 points percentage</u>

Here, it seems that the question is asking what percentage of the points possible were earned, so the whole is the 125 points possible, and the "part" is the 95 points that were earned.

\text{ratio}=\dfrac {\text{the number of points earned}}{\text{the total number of points possible}}

\text{ratio}=\dfrac {95}{125}

Dividing gives 0.76.  Multiplying by 100 gives 76.  So, 76% of points possible were earned.

You might be interested in
A perfect square is a number that has an integer square root<br><br> True or false
Sati [7]
This is true.
These are perfect squares: 4, 9, 25. These are not: 7, 8, 11
8 0
3 years ago
Read 2 more answers
Question 11
Leno4ka [110]

E
If the pre-image is dilated, the image must be congruent to the pre-image.
4 0
3 years ago
Josie has 47$ left on her checking account if she writes a check for 55$ what will josies balance be
HACTEHA [7]
She will have negative eight dollars. Thats all I can say

7 0
3 years ago
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{adjacent}{hypotenuse}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{opposite}{adjacent}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{adjacent}{opposite}&#10;\\\\\\&#10;% cosecant&#10;csc(\theta)=\cfrac{hypotenuse}{opposite}&#10;\qquad \qquad &#10;% secant&#10;sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}&#10;\qquad\qquad &#10;cos(\theta)=\cfrac{\sqrt{35}}{6}&#10;\\\\\\&#10;% tangent&#10;tan(\theta)=\cfrac{-1}{\sqrt{35}}&#10;\qquad \qquad &#10;% cotangent&#10;cot(\theta)=\cfrac{\sqrt{35}}{1}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}&#10;\\\\\\&#10;sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
Suppose a jar contains 15 red marbles and 19 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same
Kay [80]

Answer:    \bold{\dfrac{35}{187}}

<u>Step-by-step explanation:</u>

1st marble  and   2nd marble

 \dfrac{15\ red}{34\ total}       \times        \dfrac{14\ red}{33\ total}           =\dfrac{15\times 14}{34\times 33}=\dfrac{5\times 7}{17\times 11}= \boxed{\dfrac{35}{187}}

8 0
3 years ago
Other questions:
  • Victor earns a gross annual income of $64,570 and is buying a home for $125,340. He is making a 15% down payment and financing t
    6·1 answer
  • What is the actual length of the flower garden
    9·1 answer
  • 40×+4y=-24 what is the equation for y
    13·1 answer
  • Two workers finished a job in 12 days. How long would it take each worker to do the job by himself if one of the workers needs 1
    10·2 answers
  • What is 3 tenths in number form
    14·2 answers
  • Write an equation for the line below. Show work
    9·1 answer
  • I am tired of this so here is the last time and i'm gonna waste my points since nobody in the world actually cares
    6·1 answer
  • Although television HDTV converters are tested before they are placed in the installer's truck, the installer knows that 20 perc
    9·1 answer
  • Find the coordinates of the intersection of the diagonals of the parallelogram with the vertices Q(-1,3), R(5,2), S(1, - 2), and
    15·1 answer
  • Help ASAP I’ll give brainliest don’t answer of u do not know thank u Sm:)
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!