Answer:
b) volume per mol (10.237 L/mol) of the inlet gas less than of the outlet gas ( 24.378 L/mol ).
Explanation:
∴ R = 0.082 atm*L / K*mol...ideal gas constant
for entry:
T1 = 35°C + 273 = 308 K
P1 = 250 KPa * ( 0.009869 atm / KPa) = 2.467 atm
⇒(V/n)1 = (R * T1 ) / P1 = (( 0.082 atm*L / K*mol ) * (308 K )) / 2.467 atm
⇒ (V/n)1 = 10.237 L/mol ideal gas inlet
for the exit:
T2 = 35 °C + 273 = 308 K
P2 = 105 KPa * ( 0.009869 atm / KPa ) = 1.036 atm
⇒ (V/n)2 = (R * T2) / P2 = (( 0.082 * 308 )) / 1.036
⇒ (V/n)2 = 24.378 L/mol ideal gas outlet
Some examples of malleable materials are gold, silver, iron, aluminum, copper and tin.
Answer:
0.8 mL of protein solution, 9.2 mL of water
Explanation:
The dilution equation can be used to relate the concentration C₁ and volume V₁ of the stock/undiluted solution to the concentration C₂ and volume V₂ of the diluted solution:
C₁V₁ = C₂V₂
We would like to calculate the value for V₁, the volume of the inital solution that we need to dilute to make the required solution.
V₁ = (C₂V₂) / C₁ = (2mg/mL x 10mL) / (25 mg/mL) = 0.8 mL
Thus, a volume of 0.8 mL of protein solution should be diluted with enough water to bring the total volume to 10 mL. The amount of water needed is:
(10 mL - 0.8 mL) = 9.2 mL
Explanation:
Number of Cm neutrons = 242 - 96 = 146
Answer : The temperature in degree Celsius and Kelvin is, respectively.
Explanation :
The conversion used for the temperature from Fahrenheit to degree Celsius is:
where,
= temperature in Fahrenheit
= temperature in centigrade
The conversion used for the temperature from degree Celsius to Kelvin is:
where,
= temperature in Kelvin
= temperature in centigrade
As we are given the temperature in Fahrenheit is, 130
Now we have to determine the temperature in degree Celsius.
Now we have to determine the temperature in Kelvin.
Therefore, the temperature in degree Celsius and Kelvin are,