Answer:
C. Signal-to-quantization-noise ratio
Explanation:
Answer:
8 820 barrels
Explanation:
Data:
The number of barrels loaded = 9 000
cargo temperature = 35 °C
API = 44 ° C
Barrels when the cargo temperature is 55° F from the determination = 8 820 barrels.
Answer and Explanation:
considering a rigid system
fixed volume V = C
water at P1=22bar and T1=375ºC
at 22 bar Tsat =217.2ºC
so...
T1>Tsat
thus
Steam is superheated (phase at this condition)
Specific Volume, V1
V1= Vg * [ Tsup/Tsat]
V1= 0.090663* ((375+273)/(217.2+273))
V1= 0.1198 m³/kg (specific volume under this condition)
V=C, T2=195ºC
from Mollier Diagram we have that..
P2= 6bar (quality and enthalpy)
h2= 2840 KJ/kg
Superheated Steam
This question is incomplete, the complete question is;
A 1,040 N force is recorded on a hemispherical vane as it redirects a 2.5 cm- blade diameter water jet through a 180 angle.
Determine the velocity of the flowing water jet if the blade is assumed to be frictionless.
Answer: the velocity of the flowing water jet is 32.55 m/s assuming the blade is frictionless
Explanation:
Given that;
Force Ft = 1040 N
diameter d = 2.5 cm = 0.025 m
we know that; force acting on Hemispherical plate is;
Ft = 2δav²
where
a is area = π/4(0.025)²
δ is density of water = 1000 kg/m³
v is velocity = ?
now we substitute
1040 = 2 × 1000 × (π/4(0.025)²) × v²
1040 = 0.9817v²
v² = 1040 / 0.9817
v² = 1059.3867
v = √1059.3867
v = 32.5482 ≈ 32.55 m/s
Therefore the velocity of the flowing water jet is 32.55 m/s assuming the blade is frictionless