Answer:
A) 30 mH
B ) 10-ohm
Explanation:
resistor = 10-ohm
Inductor = 30mH ( l )
L = inductance
R = resistance
r = internal resistance
values of the original Inductors
Note : inductor = constant time (t) case 1
inductor + 10-ohm resistor connected in series = constant time ( t/2) case2
inductor + 10-ohm resistor + 30 mH inductance in series = constant time (t) case3
<em>From the above cases</em>
case 1 = time constant ( t ) = L / R
case 2 = Req = R + r hence time constant t / 2 = L / R + r therefore
t = 
case 3 = Leq = L + l , Req = R + r . constant time ( t )
hence Z = 
= t
A) Inductance
To calculate inductance equate case 1 to case 3
= = L / 10 = (L + 30) / ( 10 + 10 )
= 20 L = 10 L + 300 mH
10L = 300 m H
therefore L = 30 mH
B ) The internal resistance
equate case 1 to case 2
= 
R + r = 2 R therefore ( r = R ) therefore internal resistance = 10-ohm
Answer:
5 lengths away or 50-100 feet
Explanation:
I would say and from what I found 5 lengths away or 50-100 feet
Answer:
150kW
Explanation:
Energy date of air when it enters= 100kW
Energy rate of air when it leaves= 250kW
Energy rate gained by air= energy rate lost by sytem= 250-100
= 150kW
The elevation might be higher causing more rain
Answer:
Q = 2450 KJ/day
Explanation:
We are given;
The amount of moisture produced by a person while taking shower; m = 0.25 kg/person
Total number of persons in the family; N = 4
Latent heat of vaporization of water:
h_fg = 2450 KJ/kg
Since amount of moisture per person is 0.25kg per day,thus for 4 people, total mass; m_total = 4 x 0.25 = 1 kg per day
The formula for the amount of latent heat added to the space due to shower per day, is given as;
Q = m_total x h_fg
Plugging in the relevant values;
Q = 1 x 2450 = 2450 KJ/day
