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Sophie [7]
2 years ago
6

Most of the work that engineers do with fluids occurs in nature. True False

Engineering
1 answer:
zlopas [31]2 years ago
3 0
True depending the jobs
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Identify one of the advantages of 3d modeling?
Naddik [55]

Answer:

Hello Adam here! (UWU)

Explanation:

The advantages of 3D modeling for designers is not limited to productivity and coordination, it is an excellent communication tool for both the designer and end user. 3D models can help spark important conversations during the design phase and potentially avoid costly construction mishaps.

Happy to Help! (>.O)

6 0
3 years ago
Define Electromechanical systems.
dedylja [7]

Answer:

Electromechanical systems or devices are systems or devices that involves the interaction between electrical systems and mechanical systems in which the motion of mechanical parts is converted to electrical energy or made to interact with energy or in which electrical energy is converted to mechanical energy or interacts with a moving mechanical system

Therefore;

Electromechanical systems convert <u>electrical energy</u> input into a <u>mechanical energy</u> output

Explanation:

3 0
2 years ago
Con una tasa de interés de 8% por año, ¿a cuánto equivalen $10 000 de hoy, a) dentro de un año, y b) hace un año?
Contact [7]

Answer:

que hces en eeuua

Explanation:

8 0
3 years ago
Air enters a 28-cm diameter pipe steadily at 200 kPaand 208C with a velocity of 5 m/s. Air is heated as it flows, and leaves the
Alina [70]

Answer:

(a) \dot V_1 = 0.308 m³/s

(b) \dot m = 0.732 kg/m³

(c) v₂ = 5.94 m/s.

Explanation:

(a) The volume flow rate is given by the cross sectional area of the pipe × Velocity of flow of air

Diameter of pipe = 28 cm = 0.28 m

The cross sectional area, A, of the pipe = 0.28²/4×π = 0.0616 m²

Volume flow rate = 5 × 0.0616  = 0.308 m³/s

\dot V_1 = 0.308 m³/s

(b) From the general gas equation, we have;

p₁v₁ = RT₁ which gives;

p₁/ρ₁ = RT₁

ρ₁ = p₁/(RT₁)

Where:

ρ₁ = Density of the air

p₁ = 200 kPa

T₁ = 20 C =

R = 0.287 kPa·m³/(kg·K)

ρ₁ = 200/(0.287 ×293.15) = 2.377 kg/m³

The mass flow rate = Volume flow rate × Density

The mass flow rate, \dot m = 2.377×0.308 = 0.732 kg/m³

\dot m = 0.732 kg/m³

(c) The density at exit, ρ₂, is found from the the universal gas equation as follows;

ρ₂ = p₂/(RT₂)

Where:

p₂ = Pressure at exit = 180 kPa

T₂ = Exit temperature = 40°C = 273.15 + 40 = 313.15 K

∴ ρ₂ = 180/(0.287×313.15) = 2.003 kg/m³

\dot m = ρ₂×\dot V_2

\dot V_2 = \dot m/ρ₂ = 0.732/2.003 = 0.366 m³/s

\dot V_2 = v₂ × A

v₂ = \dot V_2/A = 0.366/0.0616 = 5.94 m/s.

v₂ = 5.94 m/s.

5 0
3 years ago
There are two ingredients (A and B) that will be mixed in the reactor tank. Wait for READY signal to be on (when on, it signifie
Svet_ta [14]

Answer:

Find attached of the designed PLC

Explanation:

See the attached file for the explanation.

5 0
3 years ago
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