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mr_godi [17]
3 years ago
9

How do you solve this ??

Chemistry
1 answer:
kotegsom [21]3 years ago
3 0
Answer : Option A) 2.00 eV

Explanation : The conversion of J to eV is done with the following formula;

E_{eV} = E_{J} X (6.241 X 10^{18})

Here, we have the value of particle in terms of Joules which is 3.2 X 10^{-19}

So, on substituting we get,
E_{eV} = 3.2 X 10^{-19}  X  (6.241 X 10^{18} )


E_{eV} = 1.99 eV so, it can be rounded off to 2.00 eV.
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How many grams of NaF should be added to 500 mL of a 0.100 M solution of HF to make a buffer with a pH of 3.2
Korolek [52]

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2.25g of NaF are needed to prepare the buffer of pH = 3.2

Explanation:

The mixture of a weak acid (HF) with its conjugate base (NaF), produce a buffer. To find the pH of a buffer we must use H-H equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer that you want = 3.2, pKa is the pKa of HF = 3.17, and [] could be taken as the moles of A-, the conjugate base (NaF) and the weak acid, HA, (HF). </em>

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1.017152 = [A-] / [0.0500moles]

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The mass could be obtained using the molar mass of NaF (41.99g/mol):

0.0536 moles NaF * (41.99g/mol) =

<h3>2.25g of NaF are needed to prepare the buffer of pH = 3.2</h3>
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