Bitter taste, high pH, and caustic Bitter are the characteristics of base.
<h3>What are the characteristics of base?</h3>
Bases have bitter taste, soapy feel, turn red litmus paper blue. Bases are substances that contain metal oxides or hydroxides. Its pH is higher than 7 up to 14.
So we can conclude that bitter taste, high pH, and caustic Bitter are the characteristics of base.
Learn more about base here: brainly.com/question/3948796
Answer:
One carbon atom and the nitrogen atom have nonzero formal charges.
Explanation:
The compound Acetonitrile has sixteen valence electrons as is easily San from its structure. It contains a carbon nitrogen triple bond with a lone pair of electrons on nitrogen. All atoms satisfy the octet rule and there is no hyper valent atom in the molecule.
The formal charge an carbon and nitrogen is calculated as follows;
No. of valence electron on atom - [non bonded electrons + no. of bonds]
Therefore, for carbon and nitrogen, we have;
formal charge on carbon = 4 - (0 + 4) = 0
formal charge on nitrogen = 5 - (2 + 3) = 0
Hence carbon and nitrogen both possess zero formal charges.
Answer:
Explanation:
Following are a few consequences of fossil fuels
1. It causes air pollution.
2. When they are burned, they produce toxic substances which leads to global warming.
3. Waste products are hazardous to public health and environment.
4. They are non - renewable and unsustainable.
5. Drilling fossil fuels is a dangerous process
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Explanation:
The enzyme 's active site binds to the substrate. Increasing the temperature generally increases the rate of a reaction, but dramatic changes in temperature and pH can denature an enzyme, thereby abolishing its action as a catalyst. ... When an enzyme binds its substrate it forms an enzyme-substrate complex.
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Answer:
5.004kg
Explanation:
Combustion of carbon
C+O2=CO2
from the relationship of molar ratio
mass of carbon/molar mass of carbon=volume of CO2 produced\molar vol(22.4 dm3)
mass of carbon =1000kg
atomic mass of carbon =12
volume of CO2 produced=1000×22.4/12
volume of CO2 produced =1866.6dm3
from the combustion reaction equation provided
CO2 (g) + 2NH3 (g) ⟶ CO (NH2 )2 (s) + H2 O(l)
applying the same relationship of molar ratio
no of mole of CO2=no of mole of urea
therefore
vol of CO2\22.4=mass of urea/molar mass of urea
molar mass of urea=60.06g/mol
from the first calculation
vol of CO2=1866.6dm3
mass of urea=1866.6×60.06/22.4
mass of urea=5004.82kg