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Eduardwww [97]
2 years ago
6

PLEASE HELP!!!!

Physics
2 answers:
Snezhnost [94]2 years ago
4 0

Answer:

the cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living

Explanation:

Yes that can be understood by a simple example

Suppose two people are in exam

  • A difficult and logical question came
  • The person can use his cognitive abilities faster can solve that
mestny [16]2 years ago
3 0

\large\longrightarrow Intelligence is the <u>cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living.</u>

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HELPPP ME PLEASE!!!!
andriy [413]

Answer:

c

Explanation:

3 0
2 years ago
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Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.
Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = \frac{mv}{qB}

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and  charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r =  \frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T} = 0.0328 m, or 3.28  cm.

8 0
3 years ago
A light-year measures the _______ that light travels in 1 year.
o-na [289]
<span>A light-year measures the distance that light travels in 1 year. 

Answer : B ) Distance

-Hope this helps.</span>
4 0
3 years ago
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To calibrate your calorimeter cup, you first put 45 mL of cold water in the cup, and measure its temperature to be 24.7 °C. You
drek231 [11]

Answer : The heat change of the cold water in Joules is, 1.6\times 10^3J

Explanation :

First we have to calculate the mass of cold water.

As we know that the density of water is 1 g/mL. The volume of cold water is 45 mL.

Density=\frac{Mass}{Volume}

Mass=Density\times Volume=1g/mL\times 45mL=45g

Now we have to calculate the heat change of cold water.

Formula used :

Q=m\times c\times (T_2-T_1)

where,

Q = heat change of cold water = ?

m = mass of cold water = 45 g

c = specific heat of water = 4.184J/g^oC

T_1 = initial temperature of cold water = 24.7^oC

T_2 = final temperature  = 33.4^oC

Now put all the given value in the above formula, we get:

Q=45g\times 4.184J/g^oC\times (33.4-24.7)^oC

Q=1638.036J=1.6\times 10^3J

Therefore, the heat change of cold water is 1.6\times 10^3J

4 0
3 years ago
A ball is dropped off the side of a bridge. after 1.55 s, how far has it fallen
givi [52]

Answer:

38.64 feet

Explanation:

x=x0 + vx0t + 1/2axt2

x= 0 +  0  + 1/2 X 32.17 ft/sec2 X 1.55 sec2

x = 38.64 feet

7 0
3 years ago
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