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3 years ago

Calculate the density of Saturn. Show your work. How does it compare with the density of water? Explain how this can be.

Physics

1 answer:

stepladder [879]3 years ago

4 0

Answer:

The density of Saturn is 686.81 kg/m³.

Explanation:

Mass of Saturn, $m=5.68\times 10^{26}\ kg$

Volume of Saturn, $V=8.27\times 10^{23}\ m^3$

Density of Saturn is given by its mass divided by its volume i.e.

$d=\dfrac{m}{V}$

$d=\dfrac{5.68\times 10^{26}}{8.27\times 10^{23}}$

$d=686.81\ kg/m^3$

So, the density of Saturn is 686.81 kg/m³.

The density of water is 1000 kg/m³. It is clear that the density of Saturn is less than water.

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The linear speed of the ladybug is 4.1 m/s

Explanation:

First of all, we need to find the angular speed of the lady bug. This is given by:

$\omega=\frac{2\pi}{T}$

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$\omega=\frac{2\pi}{1 s}=6.28 rad/s$

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3 years ago

Thermodynamic Processes: An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will

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Answer:

The resulting pressure is 3 times the initial pressure.

Explanation:

The equation of state for ideal gases is described below:

$P\cdot V = n \cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure.

$V$ - Volume.

$n$ - Molar quantity, in moles.

$R_{u}$ - Ideal gas constant.

$T$ - Temperature.

Given that ideal gas is compressed isothermally, this is, temperature remains constant, pressure is increased and volume is decreased, then we can simplify (1) into the following relationship:

$P_{1}\cdot V_{1} = P_{2}\cdot V_{2}$ (2)

If we know that $\frac{V_{2}}{V_{1}} = \frac{1}{3}$ , then the resulting pressure of the system is:

$P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)$

$P_{2} = 3\cdot P_{1}$

The resulting pressure is 3 times the initial pressure.

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2 years ago

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