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Nesterboy [21]
2 years ago
15

Which forces are acting on the student and the skateboard in the instant in which they are pushing off the wall? (Select all tha

t apply)
A. The force of the student pushing the wall
B.The force of gravity on the skateboard and the student
C.The force of the wall pushing on the student
D. The force of the floor pushing on the skateboard and the student
or E. Select all of the above
Physics
2 answers:
diamong [38]2 years ago
7 0
E all of the answers above correlate to the student and his skateboard
Vinil7 [7]2 years ago
5 0
Answer

E. Select all of the above

Explanation

They are all true
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PLEASE HELP 100 POINTS
tia_tia [17]

Answer:

okay, So Um,

Explanation:

BTW, There are only 50 points, brainly subtracts half of the points

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2 years ago
What is the significance of the fact that the gravitational constant, G, is a very small number and that Coulomb’s constant, k,
valina [46]
Both are constants used in the definition of Forces (gravitational and electric,respectively)

Since those constants are proportional to the magnitude of the forces:

Having a small gravitational constant explains why there is no apparent force of attraction with objects of considerable low mass (they would need to have great value of mass for the equation to give an apreciable force)

Electrical interactions are usually strong, and thus require an appropiate constant to depict the phenomenon. We deal in this case with charges really small, but the forces are in different order of magnitude.
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3 years ago
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All of the following devices are used to create an open circuit EXCEPT a:
Brrunno [24]

Answer:

I think its a fuse because everything else makes sense and is used in electrical circuits and the fuse is the only one that stands out to me  ¯\_(ツ)_/¯

4 0
3 years ago
What is approximate resistance between P and Q?<br> a) 0.5<br> b)0.8<br> c)2.0<br> d)2.2<br> e)3.6
Rufina [12.5K]

Answer:

0.5 Ohms

Explanation:

We note that the node Q is also between the resistors of 1ohm and 2ohms.

We note that the node P is also between the resistors of 2ohms and 3ohms.

Thus, all these resistors are in parallel, beween nodes P and Q

1/Re=1/R1+1/R2+1/R3

1/Re=1/1+1/2+1/3=(6+3+2)/6=11/6 [ohm^(-1)]

Re=6/11=0.54ohms

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8 0
3 years ago
After a recent snow storm, you decide to sled down a hill in Fairmount Park. You take a running start and hit the slope with an
ad-work [718]

Answer:

69.42 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (vᵢ ) = 4.9 m/s

Acceleration (a) = 4.2 m/s²

Time (t) = 4.7 s

Displacement (Δx) =?

Thus, we can obtain the displacement by using the following formula:

Δx = vᵢt + ½at²

Δx = (4.9 × 4.7) + (½ × 4.2 × 4.7²)

Δx = 23.03 + (2.1 × 22.09)

Δx = 23.03 + 46.389

Δx = 69.419 ≈ 69.42 m

Thus, the distance travelled is 69.42 m

8 0
3 years ago
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