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Musya8 [376]
3 years ago
13

How do massive stars change the atmosphere?

Physics
1 answer:
Wewaii [24]3 years ago
6 0
Not sure what you're referring to... our atmosphere is mostly nitrogen/oxygen - both gases were created by very massive stars, many times greater than our sun - our sun isn't massive enough to create the gases needed for our atmosphere...
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The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N
Hunter-Best [27]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g  = 1.63 m/s^2

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

Weight=72 kg\times 1.63m/s^2=117.36 N

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

5 0
4 years ago
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If the weight of an object is greater than the weight of the water that it displaces, which is true? 1.the object will float bec
abruzzese [7]
2) Option B...............................
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4 years ago
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1) how is the sun able to produce nuclear fusion?
Bad White [126]
2: Fusion occurs constantly on our sun.When nuclei fuse create a heavier nuclear and produce a little leftover energy in the process
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3 years ago
Which of the following factors influence the electrical resistance of a circuit?
stealth61 [152]
-- material and thickness of the interconnecting wires;

-- number, type, and configuration of all the devices
between the in- and out-terminals of the circuit ...
the points that connect to the battery;

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5 0
4 years ago
The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water
Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence  = 78.9°

<u>For blue light : </u>

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}

{sin\theta_2}=0.7323

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

<u>For red light : </u>

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,  

\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}

{sin\theta_2}=0.7373

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0
4 years ago
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