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3 years ago

How do massive stars change the atmosphere?

1 answer:

6 0

Not sure what you're referring to... our atmosphere is mostly nitrogen/oxygen - both gases were created by very massive stars, many times greater than our sun - our sun isn't massive enough to create the gases needed for our atmosphere...

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The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N

Hunter-Best [27]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g = 1.63 $m/s^2$

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

$Weight=72 kg\times 1.63m/s^2=117.36 N$

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

5 0

4 years ago

Read 2 more answers

If the weight of an object is greater than the weight of the water that it displaces, which is true? 1.the object will float bec

abruzzese [7]

2) Option B...............................

8 0

4 years ago

Read 2 more answers

1) how is the sun able to produce nuclear fusion?

Bad White [126]

2: Fusion occurs constantly on our sun.When nuclei fuse create a heavier nuclear and produce a little leftover energy in the process

6 0

3 years ago

Which of the following factors influence the electrical resistance of a circuit?

stealth61 [152]

-- material and thickness of the interconnecting wires;

-- number, type, and configuration of all the devices
between the in- and out-terminals of the circuit ...
the points that connect to the battery;

-- quality of the connections at the points where
circuit devices connect to wires or to each other.

5 0

4 years ago

The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water

Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence = 78.9°

<u>For blue light : </u>

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}$

${sin\theta_2}=0.7323$

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

<u>For red light : </u>

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}$

${sin\theta_2}=0.7373$

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0

4 years ago