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2 years ago

Give the values of a, b, and c needed to write the equation's general form.

1 answer:

5 0

The values of a, b, and c are needed to write the equation's general form will be a = 1; b = -3; c = 0.Option A is corect.

<h3>What is the equation?</h3>

A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.

Given equation;

x²-3x=0

The quadratic equation in the form is;

ax² + bx + c = 0

On putting the values of the options one by one we will get the answer;

1 x²+(-3)x+0

x²-3x=0

Hence, option A is corect.

To learn more, about equations, refer;

brainly.com/question/10413253

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Which statement about the parabola are true? Select two options

8090 [49]

Answer:

where are the options

Step-by-step explanation:

5 0

3 years ago

9471.3569 rounded to the hundred place

nadya68 [22]

Since the hundred place is the 4 and the tens place is higher than 5 ( it is 7) to round to the hundreds place it would be 9500

6 0

3 years ago

Evaluate without using a calculator (x2y-3)0+x1/3-(4x)1/2 when x = 64 and y = 27. Show work.

aleksley [76]

Given:

The expression is:

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

To find:

The value of the given expression when $x=64$ and $y=27$ .

Solution:

We have,

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

Putting $x=64$ and $y=27$ , we get

$=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}$

It can be written as

$=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}$

$=1+4-2(8)$ $[\because a^0=1,a\neq 0]$

$=5-16$

$=-11$

Therefore, the value of the given expression $-11$ when $x=64$ and $y=27$ .

4 0

3 years ago

Use completing the square to solve this quadratic equation.

borishaifa [10]

Step-by-step explanation:

x² + 6x + 9 = 2

(x + 3)² = 2

x + 3 = ±sqrt(2)

x = -3 ± sqrt(2)

so, B and D are correct.

control :

(-3 + sqrt(2))² + 6(-3 + sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) - 18 + 6sqrt(2) + 9 = 2

2 = 2

correct

(-3 - sqrt(2))² + 6(-3 - sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) - 18 - 6sqrt(2) + 9 = 2

2 = 2

correct

(3 + sqrt(2))² + 6(3 + sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) + 18 + 6sqrt(2) + 9 = 2

38 + 12sqrt(2) = 2

wrong.

(3 - sqrt(2))² + 6(3 - sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) + 18 - 6sqrt(2) + 9 = 2

38 - 12sqrt(2) = 2

wrong.

7 0

3 years ago

What is the domain of the function in this table?

Vera_Pavlovna [14]

Where's the other table?

3 0

3 years ago