To be able to solve equations 3 and 4 by elimination, each equation needs to be multiplied by something, Drag a red number to th

Question

2 years ago

5

e red box for equation 3 and a brown number to the brown box for equation 4.

1 answer:

marishachu [46] · Answer 1 · 2023-03-22T03:20:30+03:00

The solution to the equation 3 and 4 by elimination is x = -2 and y = -2

<h3>Simultaneous equation</h3>

2x = 3y + 2. (1)

3x = 5y + 4. (2)

2x - 3y = 2. (3)

3x - 5y = 4 (4)

6x - 9y = 6. (5)

6x - 10y = 8. (6)

-10y - (-9y) = 8 - 6

-10y + 9y = 2

-y = 2

y = -2

2x - 3y = 2. (3)

2x - 3(-2) = 2

2x + 6 = 2

2x = 2 - 6

2x = - 4

x = -4/2

x = -2

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