To be able to solve equations 3 and 4 by elimination, each equation needs to be multiplied by something, Drag a red number to th
e red box for equation 3 and a brown number to the brown box for equation 4.
1 answer:
The solution to the equation 3 and 4 by elimination is x = -2 and y = -2
<h3>Simultaneous equation</h3>
2x = 3y + 2. (1)
3x = 5y + 4. (2)
2x - 3y = 2. (3)
3x - 5y = 4 (4)
- Multiply (3) by 3 and (4) by 2
6x - 9y = 6. (5)
6x - 10y = 8. (6)
- subtract (5) from (6) to eliminate x
-10y - (-9y) = 8 - 6
-10y + 9y = 2
-y = 2
y = -2
- substitute y = -2 into (3)
2x - 3y = 2. (3)
2x - 3(-2) = 2
2x + 6 = 2
2x = 2 - 6
2x = - 4
x = -4/2
x = -2
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In the equation you have to replace all x's with -1
f (-1) = (-1)^2 - 8(-1) +5
f (-1) = 1 + 8 + 5
f (-1) = 14
the f(-1) stand for the function of -1. it is also equivalent to y
I don’t understand the language
Answer:
a = √10
Step-by-step explanation:
a² + b² = c²
a² + 9² = (√91)²
a² + 81 = 91
a² = 10
a = √10
hope this helps :)