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1 year ago

Suppose the carts collided on a surface that had a slight incline to it. Would you expect the momentum to be conserved

Physics

1 answer:

lesantik [10]1 year ago

7 0

Momentum is conserved when carts are collided on a slanting plane.

To find the answer, we need to know about the conversation of momentum.

<h3>What's the conversation of momentum?</h3>

Conservation of linear momentum says the total momentum before the collision and after the collision remains the same.
Mathematically, m1u1+m2u2 = m1v1+m2v2

<h3>How is the momentum conserved when collision occurs on a slanting plane?</h3>

On a slanting plane, the velocity has two components,

horizontal component
horizontal component Vertical component

So, its momentum has also similar two components.
The momentum is conserved along horizontal direction and vertical direction separately.

Thus, we can conclude that the momentum is conserved when carts are collided on a slanting plane.

Learn more about the conversation of momentum here:

brainly.com/question/7538238

#SPJ4

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2 years ago

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2 years ago

A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication

koban [17]

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r = 4.24x10⁴ km.

Explanation:

To find the radius of such an orbit we need to use Kepler's third law:

$\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}$

<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km. </em>

From equation (1), r₁ is:

$r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}$

$r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}$

$r_{1} = 4.24 \cdot 10^{4} km$

Therefore, the radius of such an orbit is 4.24x10⁴ km.

I hope it helps you!

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3 years ago