When a car moves up a hill with constant

It takes 20s for 3x10^6 electrons to flow through a wire ,what is the current?

Elina [12.6K]

Answer:

Explanation:

The variables we know and are given are:

time, t = 20s

Charge, Q = 3x1-^-6 electrons, which is just 3x10^-6C (C stands for Coulombs, which is the unit for Charge)

We need to find the current, I, and since we know Q and t we can substitute these values into the given equation:

I=Q/t (which if you look at what the RHS is saying, its Charge over time, or more literally means the amount of charge passing a point over a period of time)

If we substitute these values, we will get I as:

I = Q / t

I = 3x10^-6 / 20

I = 1.5x10^-7 A

Hope this helps!

6 0

2 years ago

An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below

grin007 [14]

<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let $P$ be the pressure at a point.

Let $p$ be the density fluid at a point.

Let $v$ be the velocity of fluid at a point.

Bernoulli's equation states that $P+\frac{1}{2}pv^{2}+pgh=constant$ for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let $p_{up}$ be the pressure of a point just above the wing.

Let $p_{do}$ be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

$\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}$

So, $p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa$

Force is given by the product of pressure difference and area.

Given that area is $27ms^{2}$ .

So,lifting force is $16398.48\times 27=442758.96N$

6 0

3 years ago

Rx: hydrochloric acid 2 percent solution 500 ml. your stock solution of hydrochloric acid is 10 percent. how much of the stock s

Allisa [31]

100 ml

100 ml of the stock solution is required to prepare the order.

We know that C1V1 = C2V2

where C1= 2%

V1 = 500ml

C2= 10%

V2 = ?

V2 = C1V1 / C2

= 500 * 2% / 10%

=100

V2 = 100 ml

<h3>What is meant by stock solution?</h3>

A stock solution is a sizable amount of a typical reagent in a standardized concentration, like sodium hydroxide or hydrochloric acid.
This phrase is frequently used in analytical chemistry while doing operations like titrations where it's crucial to employ precise solution concentrations.

<h3>What distinguishes a standard solution from a stock solution?</h3>

The main distinction between stock solution and standard solution is that the former is a highly concentrated solution while the later is a solution whose concentration is precisely known.
Because standard solutions frequently arrive as stock solutions, the phrases "stock solution" and "standard solution" are connected.

To learn more about stock solution preparation visit:

brainly.com/question/14667249

#SPJ4

8 0

1 year ago

If the pH of a solution decrease's, is the solution getting more acidic or lees acidic

enyata [817]

Answer:

The solution becomes more acidic.

Explanation:

As the pH of a solution decreases, the concentration of hydrogen ions [H+] increases. Acidic solutions have a higher concentration of hydrogen ions and a lower pH.

I hope this helped. :)

6 0

2 years ago

hich of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field?Check

leonid [27]

Explanation:

The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :

$F=I(L\times B)$

or

$F=ILB\ sin\theta$

Where

$\theta$ is the angle between length and the magnetic field

The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.

So, the correct options are :

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
.The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

7 0

3 years ago