Answer:
T = 4.905[N]
Explanation:
In order to solve this problem we must perform a sum of forces on the vertical axis.
∑Fy = 0
We have two forces acting only, the weight of the body down and the tension force T up, as the body does not move we can say that it is system is in static equilibrium, therefore the sum of forces is equal to zero.
![T-m*g=0\\T=0.5*9.81\\T=4.905[N]](https://tex.z-dn.net/?f=T-m%2Ag%3D0%5C%5CT%3D0.5%2A9.81%5C%5CT%3D4.905%5BN%5D)
The answer is True. The amount force exerted by any object is directly proportional to its mass. This means that our planet is exerting more gravitational force to Angelina, and Angelina is also exerting a gravitational force on our planet directly proportional to her mass. Angelina is actually falling towards the center of the earth,and also our planet is also moving towards Angelina, but it seems negligible with respect to Angelina.Our Sun is so massive that it held our planet in its orbit because of its gravitational force.
Answer:1.71 m/s
Explanation:
Given
mass of Susan ![m=12 kg](https://tex.z-dn.net/?f=m%3D12%20kg)
Inclination ![\theta =30^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%20%3D30%5E%7B%5Ccirc%7D)
Tension ![T=29 N](https://tex.z-dn.net/?f=T%3D29%20N)
coefficient of Friction ![\mu =0.18](https://tex.z-dn.net/?f=%5Cmu%20%3D0.18)
Resolving Forces Along x axis
![F_x=T\cos \theta -f_r](https://tex.z-dn.net/?f=F_x%3DT%5Ccos%20%5Ctheta%20-f_r)
where
![F_y=mg-N-T\sin \theta](https://tex.z-dn.net/?f=F_y%3Dmg-N-T%5Csin%20%5Ctheta%20)
since there is no movement in Y direction therefore
![N=mg-T\sin \theta](https://tex.z-dn.net/?f=N%3Dmg-T%5Csin%20%5Ctheta%20)
and ![f_r=\mu N](https://tex.z-dn.net/?f=f_r%3D%5Cmu%20N)
Thus ![F_x=T\cos \theta -\mu N](https://tex.z-dn.net/?f=F_x%3DT%5Ccos%20%5Ctheta%20-%5Cmu%20N)
![F_x=25.114-18.558](https://tex.z-dn.net/?f=F_x%3D25.114-18.558)
![F_x=6.556 N](https://tex.z-dn.net/?f=F_x%3D6.556%20N)
Work done by applied Force is equal to change to kinetic Energy
![F_x\cdot x=\frac{1}{2}\cdot mv_f^2-\frac{1}{2}\cdot mv_i^2](https://tex.z-dn.net/?f=F_x%5Ccdot%20x%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20mv_f%5E2-%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20mv_i%5E2)
![6.556\times 2.7=\frac{1}{2}\cdot 12\times v_f^2](https://tex.z-dn.net/?f=6.556%5Ctimes%202.7%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%2012%5Ctimes%20v_f%5E2)
![v_f^2=\frac{6.556\times 2.7\times 2}{12}](https://tex.z-dn.net/?f=v_f%5E2%3D%5Cfrac%7B6.556%5Ctimes%202.7%5Ctimes%202%7D%7B12%7D)
![v_f^2=2.95](https://tex.z-dn.net/?f=v_f%5E2%3D2.95)
The block has the greatest average power provided is bock m.
<h3>What is instantaneous power?</h3>
- This is the product of force and velocity exerted on an object.
Mathematically instantaneous power is calculated as;
P = Fv
where;
- F is the applied force
- v is the velocity
Both blocks (m and 2m) will experience the same force but different velocity.
The smaller block (m) will experience greater velocity.
Thus, the block has the greatest average power provided is bock m.
Learn more about instantaneous power here: brainly.com/question/8893970
1. Traveling by car means you have specific roads to follow. You won’t be able to go straight to Banning high from POLAHS. The 8.4km will be defined as distance. Traveling by helicopter you don’t have roads to follow that means you can fly directly to banning high. 6.8km will be defined as displacement.
2. A) 400m
B)0m
C)d=1/2(vi+vf)t
400=1/2(0+vf)92
8.7m/s
D) 0m/s
E) Not sure but instantaneous velocity refer to velocity at a given point. Average velocity is just the average. Usually instantaneous velocity won’t be same as the average velocity.
Plz like if it helped.