Answer:
2.16 moles of Au₂S₃ are decomposed.
Explanation:
Given data:
Number of moles of gold (III) sulfide decomposed = ?
Number of moles of gold metal formed = 4.32 mol
Solution:
Chemical equation:
Au₂S₃ → 2Au + 3S
Now we will compare the moles of Au₂S₃ with gold metal.
Au : Au₂S₃
2 : 1
4.32 : 1/2×4.32 = 2.16
2.16 moles of Au₂S₃ are decomposed.
Answer:
b. halogens
Explanation:
The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Halogens are very reactive these elements cannot be found free in nature. Their chemical properties are resemble greatly with each other. As we move down the group in periodic table size of halogens increases that's way fluorine is smaller in size as compared to other halogens elements. Their boiling points also increases down the group which changes their physical states.
Answer: The order of increasing lattice energy is 
Explanation: Lattice energy is defined as the energy required to break the intermolecular force that is responsible for the formation of a lattice.
Melting point is defined as the temperature at which solid gets converted into liquid due to the weakening of the bonds in the solid form.
- Relation between lattice energy and Melting point:
The relationship between these two is direct.
More the melting point of a compound, more will be its lattice energy.
Order of increasing Lattice energy will be:
Answer:
B. Both electrons of Mg should be transferred to one O.
Explanation:
Metals react by loosing electrons while non metals react by gaining electrons.
Reactions occur as each element strives to attain an octet electron configuration in the outer energy level.
It is easier for magnesium to loose 2 electrons than to gain six because loosing the two requires less energy.
Oxygen on the other hand reacts by gaining the two electrons lost by magnesium since it is easier to gain the two than to loose the six. Gaining the two electrons for oxygen requires less energy than loosing the six.
In summary, magnesium looses two electrons that are transferred to oxygen.
Answer:
Explanation:
You should allow the solvent to drop to the level of the adsorvent, so it would never run dry.
When you let your sample to run dry it will never finish to flow from the adsorbent depending of it polarity.
Water should not be used because it can dissolve the adsorbent.
You could use another technique to identify the compound, as an infrared or a ultraviolet detector. You can also, if you know the compounds, identify it for the retention time, for example, if you need to detect two compounds, one more polar than the other, and use a polar adsorbent and a non-polar solvent, the first compound to exit the column will be the less polar one, because it will have a bigger interaction with the solvent than the stationary phase (adsorbent) and will go faster, the second will be the more polar one, because it will have a bigger interaction with the stationary phase.
