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ziro4ka [17]
2 years ago
11

The coordinates of the vertices of △ABC are A(−2,2), B(5,−3), and C(−4,−1). Identify the perimeter of △ABC. Round each side leng

th to the nearest tenth before adding.
Mathematics
1 answer:
Minchanka [31]2 years ago
7 0

The perimeter of the triangle is 21.4 units

<h3>How to determine the perimeter?</h3>

The points are given as:

A(−2,2), B(5,−3), and C(−4,−1)

Calculate the side lengths using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2

So, we have:

AB = \sqrt{(-2 -5)^2 + (2 + 3)^2} = 8.6

AC = \sqrt{(-2 +4)^2 + (2 + 1)^2} = 3.6

BC = \sqrt{(5+4)^2 + (-3 + 1)^2} = 9.2

The perimeter is then calculated as:

P = AB + AC + BC

This gives

P = 8.6 + 3.6 + 9.2

Evaluate

P = 21.4

Hence, the perimeter of the triangle is 21.4 units

Read more about perimeter at:

brainly.com/question/24571594

#SPJ1

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