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faust18 [17]
3 years ago
7

Which statement about gases is true?

Chemistry
2 answers:
Whitepunk [10]3 years ago
7 0

Answer:

they are made up of hard spheres that are in random motion

Romashka-Z-Leto [24]3 years ago
5 0

Answer:

D) They are made up of hard spheres that are in random motion.

Explanation:

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If a Kleenex box has a length of 8cm, width or 2cm, and a height of 4cm what is the volume of the Kleenex box?
Anettt [7]

Answer:

The volume of the Kleenex box is 64 cm.

Explanation:

Volume = B x W x H

So:      V = 8cm x 2cm x 4cm = 64cm

3 0
3 years ago
I WILL MARK BRAINLISET FOR WHOEVER GETS THIS RIGHT! A pot is placed on a gas flame, and the water inside the pot begins to boil.
NNADVOKAT [17]

Answer:

B.     Warm water rises within the pot.?

Explanation

<em>There wasn't enough information given for me to safely determine the correct answer.</em>

8 0
3 years ago
Which of the following models a synthesis reaction?
Nuetrik [128]

Answer: D

Explanation: i’m right

5 0
3 years ago
Describe the results of a physical change and list<br> three examples of physical change.
Alex Ar [27]

Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.

Ex: cutting a paper, gaining weight, cutting hair

8 0
3 years ago
What is the wavelength of radiation emitted when an electron goes from the n = 7 to the n = 4 level of the Bohr hydrogen atom? G
Phantasy [73]

Answer:

the wavelength of radiation emitted  is \mathbf{\lambda= 2169.62 \ nm}

Explanation:

The energy of the Bohr's hydrogen atom can be expressed with the formula:

\mathtt{E_n =- \dfrac{13.6\ ev}{n^2}}

For n = 7:

\mathtt{E_7 =- \dfrac{13.6\ ev}{7^2}}

\mathtt{E_7 =-0.27755 \ eV}

For n = 4

\mathtt{E_4=- \dfrac{13.6\ ev}{4^2}}

\mathtt{E_4 =- 0.85\ eV}

The  electron goes from the n = 7 to the n = 4, then :

\mathtt{E_7-E_4 = (-0.27755 - (-0.85) ) \ eV}

\mathtt{= 0.57245\ eV}

Wavelength of the radiation emitted:

\mathtt{\lambda= \dfrac{hc}{0.57245 \ eV}}

where;

hc  = 1242 eV.nm

\mathtt{\lambda= \dfrac{1242 \ eV.nm }{0.57245 \ eV}}

\mathbf{\lambda= 2169.62 \ nm}

4 0
3 years ago
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