Question

A charge of 5.4 C experiences a force of 25.0 in an electric field. What is the strength of electric field at that point ? If the 5.4 C is replaced by a charge of half the magnitude, 2.7 C, how much force would this charge experience at that point ? Remember to identity all of your data, write the equation, and show your work. (5 points)

Answer 1

The strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and  12.38 N.

What is the electric field strength?

The electric field strength is defined as the ratio of electric force to charge.

Given data;

q₁ = 5.4 C

F₁ is the electric force in case1

E is the electric field =?

F₂ is the electric force in case 2

q₂ is the charge 2

The strength of the electric field at that point is;

F₁=Eq₁

E₁=F/q₁

E₁=25.0 N / 5.4 C

E₁=4.587 N/C

The force would this charge experience at that point when the charge is 2.7 C;

F₂=Eq₂

F₂=4.587 N/C × 2.7 C

F₂ = 12.38 N

Hence the strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and  12.38 N.

To learn more about the electric field strength, refer to the link;

brainly.com/question/4264413

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