Thermonuclear fusion is when matter is heated to a high degree
Answer:
maximum possible temperature is 34.088°C
Explanation:
Given data
power output Q = 37 kW
volume flow rate = 11 x 10^-5 m3/s
temperature t = 14°C
to find out
maximum possible temperature T
solution
we can say
total water volume = 4 residents × volume flow
total water volume = 4 × 11 x 10^-5 = 44 × 10^-5 m³/s
so we say total water mass = 1000 × volume
total water mass = 1000 kg/m³ × 44 × 10^-5
total water mass = 0.44 kg
we know
dQ/dt = (dm/dt)× (S)× ( T - t)
so here we know specific heat of water S = 4.186 joule/gram °C
37 = 0.44 × 4.186 × (T-14)
T = 34.088°C
maximum possible temperature is 34.088°C
Answer:
Explanation:
ω =
k = 2.5 N/m
m = 10 kg
ω = .5 rad /s
x(t) = A cos(ωt + φ₀)
When t = 0 , x(t) = 0
0 = A cos(ωx 0 + φ₀)
cos φ₀ = 0
φ₀ = π /2
x(t) = A cos(ωt +π /2 )
Putting the value of ω
x(t) = A cos(.5 t +π /2 )
Differentiating on both sides
dx(t)/dt = - .5 A sin(.5 t +π /2 )
v(t) = - .5 A sin(.5 t +π /2 )
Given t =0 , v(t) = -5 m/s
-5 = - .5 A sin(.5 x0 +π /2 )
-5 = - .5 A sinπ /2
A = 10 m
x(t) = 10 cos( .5 t +π /2 )
b )
when t = π ( 3.14 s )
x(t) = - 10 m
when t = 2π ( 6.28s )
x(t) = 0
when t = 3π ( 9.42 s )
x(t) = 10 m
and so on
Answer:
unit =1.83
Explanation:
The cooling load is due to people, lights, and heat transfer through the walls and the windows so. The total cooling load of the room is determined from
(Equation 1) Q cooling = Q lights + Q people + Q heat gain
there fore
Q cooling = 10 x 100 W = 1 KW
Q people = 40 x 360 KJ/h = 4 KW
Q heat gain = 15.000 kJ/h = 4.17 KW
we replace the values in Equation 1
Q cooling = Q lights + Q people + Q heat gain
Q cooling = 1 + 4 +4.17
Q cooling = 9.17 KW
Thus the number of air — conditioning units required is
9.17 KW /5 KW unit =1.83