Answer:
Option A. Rectangle
Step-by-step explanation:
we know that
If a cross section of the paperweight is cut parallel to the base, then the shape of the cross section will be equal to the base
The base is a rectangle with dimensions length 10 cm, width 4 cm
therefore
The cross section is a rectangle with dimensions length 10 cm, width 4 cm
Let Q= the number of quarters and D= the number of dimes.
Q+D= 40 coins
0.25Q+0.1D= $7.75
Rewrite equation 1 as: D = 40-Q and substitute into equation 2
0.25Q+0.1(40-Q)= 7.75 Simplify the left side
0.25Q+4-0.1Q= 7.75 Subtract 4 from both sides
0.25Q-0.1Q= 3.75 Convime like terms on left side
0.15Q= 7.75 Divide both sides by 0.15
Q=25 and D= 40-Q
D= 40-25 which is 15
So Jenna had 25 quarters and 15 dimes.
<span>To check multiply 25 x 25 and 15x10 which equals 625 and 150 this equals 775 so this is 7.75</span>
2x-8=x+4
Get the x to the other side and the 8 to the opposite
2x-x=4+8
X=12
Answer:the nth term of the sequence, Tn= -3n +12
Step-by-step explanation:
The nth term of an arithmetic progression is given as
Tn= a+ (n-1) d
where a= first term
and d = common difference
In this sequence, 9, 6 ,3 ,0, -3, -6 we can see that the number is decreasing by 3
The first term, a= 9
and common difference, d = -3
using our formulae
Tn= a+ (n-1) d
Tn= 9 + ( n-1) -3
Tn=9- 3n+ 3
Tn= -3n +12
Answer:
Step-by-step explanation:
Each ticket is $15. The number of tickets is what we are trying to solve for. The class spends a certain amount of money to prepare for the formal. They hope that the money they make in ticket sales is MORE than what they spend. The expression that represents the number of tickets at $15 each is 15x, where x is the number of tickets. They hope that the sales are greater than what they spend, so what we have so far is
15x >
Greater than what, though? What do they spend? They spend 600 for the food, so
15x > 600...
but they also have to print a certain, unknown number of tickets at .50 each. The expression that represents the printing of each ticket is .5x (we can drop the 0; it doesn't change the answer or make it wrong if we drop it off). So the cost for this affair is the food + the printing.
15x > 600 + .5x
Solve this inequality for x. Begin by subtracting .5 from both sides to get
14.5x > 600 so
x > 41.3
Because we are not selling (or printing) .3 of a ticket, it's safe to say (and also correct!) that they need to sell (and print) 41 tickets. If they sell 41 tickets, the profit is found by
15(41) > 600 + .5(41)
615 > 600
This means that at 41 tickets, they make a profit. At 40 tickets, the inequality looks like this:
15(40) > 600 + .5(40) and
600 > 620. This is not true, so 40 tickets isn't enough.