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bekas [8.4K]
2 years ago
6

What are coefficients in the expression 2+6+10b-8a

Mathematics
1 answer:
tiny-mole [99]2 years ago
5 0

\boldsymbol{Answer:} 10 and -8 ✅

\boldsymbol{Step-by-step\;explanation:}

Hii, do you need to know the co-efficients in the expression "\boldsymbol{2+6+10b-8a}"? No problem! (:

<h3><u>What are Co-efficients?</u></h3>

A "co-efficient" is a number that comes before a variable.

Here there are only two such numbers: "10" and "-8"; 10 comes before b, and -8 comes before a. 2 and 6 don't come before any variables at all, so they are not co-efficients.

Voila! There's our solution, cheers! (:

--

Hope that this helped! Best wishes.

\it Reach\;far.\;Aim\;high.\;Dream\;big.

\bigstar\underbrace

--

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Need help ASAP.
hram777 [196]

Answer:

Option A. Rectangle

Step-by-step explanation:

we know that

If a cross section of the paperweight is cut parallel to the base, then the shape of the cross section will be equal to the base

The base is a rectangle with dimensions length 10 cm, width 4 cm

therefore

The cross section is a rectangle  with dimensions length 10 cm, width 4 cm

3 0
3 years ago
every evening jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she
Darya [45]
Let Q= the number of quarters and D= the number of dimes.
Q+D= 40 coins
0.25Q+0.1D= $7.75
Rewrite equation 1 as: D = 40-Q and substitute into equation 2
0.25Q+0.1(40-Q)= 7.75 Simplify the left side
0.25Q+4-0.1Q= 7.75 Subtract 4 from both sides
0.25Q-0.1Q= 3.75 Convime like terms on left side
0.15Q= 7.75 Divide both sides by 0.15
Q=25 and D= 40-Q
D= 40-25 which is 15
So Jenna had 25 quarters and 15 dimes.
<span>To check multiply 25 x 25 and 15x10 which equals 625 and 150 this equals 775 so this is 7.75</span>
8 0
3 years ago
Solve for x.<br><br> 2(x-4)=x + 4 <br><br> X=___
guapka [62]
2x-8=x+4
Get the x to the other side and the 8 to the opposite
2x-x=4+8
X=12
6 0
3 years ago
The terms in the sequence decrease by the same amount each time:
luda_lava [24]

Answer:the nth term of the sequence, Tn= -3n +12

Step-by-step explanation:

The nth term of an arithmetic progression is given as

Tn=  a+ (n-1) d

where a= first term

and d = common difference

In this sequence, 9, 6 ,3 ,0, -3, -6 we can see that  the number is decreasing by 3

The first term, a= 9

and common difference, d = -3

using our formulae

Tn=  a+ (n-1) d

Tn= 9 + ( n-1) -3

Tn=9- 3n+ 3

Tn= -3n +12

7 0
3 years ago
The 8th grade is selling tickets to the 8th grade formal.The cost per ticket is $15.The decorations and food cost $600,and each
MArishka [77]

Answer:

Step-by-step explanation:

Each ticket is $15.  The number of tickets is what we are trying to solve for.  The class spends a certain amount of money to prepare for the formal.  They hope that the money they make in ticket sales is MORE than what they spend.  The expression that represents the number of tickets at $15 each is 15x, where x is the number of tickets.  They hope that the sales are greater than what they spend, so what we have so far is

15x >

Greater than what, though?  What do they spend?  They spend 600 for the food, so

15x > 600...

but they also have to print a certain, unknown number of tickets at .50 each.  The expression that represents the printing of each ticket is .5x (we can drop the 0; it doesn't change the answer or make it wrong if we drop it off).  So the cost for this affair is the food + the printing.

15x > 600 + .5x

Solve this inequality for x.  Begin by subtracting .5 from both sides to get

14.5x > 600 so

x > 41.3

Because we are not selling (or printing) .3 of a ticket, it's safe to say (and also correct!) that they need to sell (and print) 41 tickets.  If they sell 41 tickets, the profit is found by

15(41) > 600 + .5(41)

615 > 600

This means that at 41 tickets, they make a profit.  At 40 tickets, the inequality looks like this:

15(40) > 600 + .5(40) and

600 > 620.  This is not true, so 40 tickets isn't enough.

8 0
3 years ago
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